Answer:
<em>dear </em><em>option</em><em> </em><em>C </em><em>(</em><em>2</em><em>,</em><em>4</em><em>,</em><em>6</em><em>)</em><em> </em><em>is </em><em>correct</em><em> </em><em>for </em><em>this </em><em>question</em>
<em>as,</em>
<em>domain </em><em>=</em><em> </em><em>is </em><em>all </em><em>set </em><em>of </em><em>input </em><em>values</em>
<em>and</em>
<em>range </em><em>=</em><em> </em><em>is </em><em>all </em><em>set </em><em>of </em><em>output </em><em>value</em>
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>u </u></em><em><u>dear!</u></em>
Answer: 36
Since the sum of the ratios is 5+7=12
the total number of students must be divisible by 12
The only number within the given range is 36
Answer:
29.2
Step-by-step explanation:
Mean = 21.4
Standard deviation = 5.9%
The minimum score required for the scholarship which is the scores of the top 9% is calculated using the Z - Score Formula.
The Z- score formula is given as:
z = x - μ /σ
Z score ( z) is determined by checking the z score percentile of the normal distribution
In the question we are told that it is the students who scores are in the top 9%
The top 9% is determined by finding the z score of the 91st percentile on the normal distribution
z score of the 91st percentile = 1.341
Using the formula
z = x - μ /σ
Where
z = z score of the 91st percentile = 1.341
μ = mean = 21.4
σ = Standard deviation = 5.9
1.341= x - 21.4 / 5.9
Cross multiply
1.341 × 5.9 = x - 21.4
7.7526 = x -21.4
x = 7.7526 + 21.4
x = 29.1526
The 91st percentile is at the score of 29.1526.
We were asked in the question to round up to the nearest tenth.
Approximately, = 29.2
The minimum score required for the scholarship to the nearest tenth is 29.2 .
The answer is 20/72 or 5/18
Answer:
tax=$0.18
Step-by-step explanation:
total cost = $2.18