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Bad White [126]
3 years ago
12

Solve for the value of v. (56+6) (40+3)

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

2666 if you multiply the sum of the parenthesis

but if you add them then the answer is 105

Step-by-step explanation:

56+6=62

40+3=43

62•43= 2666

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Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -
irina [24]

Answer:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Step-by-step explanation:

Given

T:R^3->R^2

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

Required

Find the standard matrix

The standard matrix (A) is given by

Ax = T(x)

Where

T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

Ax = T(x) becomes

Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

The x on both sides cancel out; and, we're left with:

A = [T(e_1)\ T(e_2)\ T(e_3)]

Recall that:

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

In matrix:

(a,b) is represented as: \left[\begin{array}{c}a\\b\end{array}\right]

So:

T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]

T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]

T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]

Substitute the above expressions in A = [T(e_1)\ T(e_2)\ T(e_3)]

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Hence, the standard of the matrix A is:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

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3 years ago
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stich3 [128]
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Hope this is of great help to you, and happy studying~!
~Mistermistyeyed.
8 0
3 years ago
Simplify -8 (-m + 3)
Helga [31]

8(-m+3)

Step by step solution :

Step  1  :

Equation at the end of step  1  :

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Step  2  :

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Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

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diamong [38]

Answer:

2/3

Step-by-step explanation:

2/6=1/3

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3 years ago
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