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qaws [65]
3 years ago
8

JKLM is a rhombus with an area of 75 square metres. Plz help with mark brainiest !!

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

OJ=5 m

Step-by-step explanation:

Area of rhombus=1/2 d1 *d2

75=1/2*15*d2

75*2/15=d2

10=d2

Therefore, d2=6

d2=10

JL=10

2OJ=10 [ Diagonals of rhombus bisect each other perpendicularly]

OJ=5 m

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
2 years ago
What is the value of (6-2) with the exponet 3? write your anewer as a whole number.
frozen [14]
64 6-2=4 then 4 times 4= 16 times 4 equals 64
4 0
2 years ago
Vertex of -2(x+3)^2+7
alekssr [168]

Answer:

The vertex is (-3, 7)

Step-by-step explanation:

As the equation is already in 'rectangular form), to work out the vertex, we can just compare this equation to that of the standard parabola y = x^2, and in particular, consider how it has been translated:

the (x+3) part moves the graph the the left 3 (i.e in the negative direction), while the +7 moves the graph up 7.

So as the vertex of the simple parabola y = x^2 is (0,0), the vertex of this graph is just (-3,7).

Note that the -2 at the front doesn't impact this vertex - this -2 just changes the 'scale' of the parabola (i.e makes it more narrow, and also turns it upside down as it's a negative number).

6 0
3 years ago
uppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5
Marizza181 [45]

Answer:

P(x \le 3.24) = 0.97725

Step-by-step explanation:

Given

\bar x = 2.5

\sigma = 0.37

Required

Percentage that is not more than 3.24

The above implies that:

x = 3.24

Calculate z score

z = \frac{x - \bar x}{\sigma}

z = \frac{3.24 - 2.5}{0.37}

z = \frac{0.74}{0.37}

z = 2

So, the probability is represented s:

P(x \le 3.24) = P(z \le 2)

From z probability

P(z \le 2) = 0.97725

Hence:

P(x \le 3.24) = 0.97725

6 0
2 years ago
Which situation is best represented by a negative number?
lara [203]
I would say D............
3 0
3 years ago
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