Answer:
A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).
Hope it helped.
please mark brainliest
10w^7 is the answer I’m pretty sure
Answer:
good u?
Step-by-step explanation:
I'll do the first one to get you started
So we have g(f(x)) which means that we start with g(x) and replace the 'x' with 'f(x)' to get g(f(x))
g(x) = ( x - 4 )/2
g(f(x)) = ( f(x) - 4)/2 .... replace every x with f(x)
g(f(x)) = (2x+4-4)/2 .... replace f(x) on the right side with 2x+4
g(f(x)) = (2x+0)/2
g(f(x)) = (2x)/2
g(f(x)) = 1x/1
g(f(x)) = 1x
g(f(x)) = x
Let me know if you need help with the other one.
Hi there!
x - 3y = 9
x = 9 + 3y
-4x + y = 8
-4(9+3y) + y = 8
-36 - 12y + y = 8
-36 - 11y = 8
-11y = 44
-y = 4
y = -4
x - 3y = 9
x - 3(-4) = 9
x + 12 = 9
x = 21
So, your answers are y = -4 and x = 21.
Hope this helps!
