Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
The answer is 15 because absolute deviation means a number of units a certain number is for 0. So, both 15 and -15 would have an absolute deviation of 15 because both numbers are 15 units away from 0. Hope I helped! Please rate me the Brainliest!
Answer:
10
Step-by-step explanation:
Thw statement that's true for the function g is g(-13) = 20.
<h3>How to illustrate the information?</h3>
From the information given, the function, g, has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45.
In this case, g(-13) = 20. Here, x = -13 is in the domain and 20 is also in the range. Therefore, this is true for g.
Learn more about functions on:.
brainly.com/question/10684895
#SPJ1
