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maxonik [38]
3 years ago
8

Write an equation that expresses the relationship. Use k as the constant of variation.

Mathematics
1 answer:
Kruka [31]3 years ago
6 0

Step-by-step explanation:

x = k/m

hope this helps. good luck!

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joja [24]

Answer:

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3 years ago
A car is traveling at a rate of 90 kilometers per hour. What is the car's rate in miles per hour? How many miles will the car tr
ser-zykov [4K]

Answer:

14.065

Step-by-step explanation:

First you wanna transfer it from kilometers to miles.

if 1 mile is = to 1.6 kilometers that is the same as saying

1/1.6, but because we are using 90 we plug it in and it becomes: 90/1.6 which gives you 56.25.

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3 0
3 years ago
Plot the points A(9, 11) and B(–3, –5). Find midpoint M of AB. Then show that AM = MB and AM + MB =AB
Alex_Xolod [135]

Answer:

The midpoint is (3, 3).

Step-by-step explanation:

We are given the two points A(9, 11) and B(-3, -5).

The midpoint is given by:

\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)

So:

\displaystyle M =  \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)

The midpoint is (3, 3).

We want to show that AM = MB.

We can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

The distance between A(9, 11) and M(3, 3) will then be:

AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10

And the distance between B(-3, -5) and M(3, 3) will be:

MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10

So, AM = MB = 10.

Since AM = MB = 10, AM + MB = 10 + 10 = 20.

So, we want to prove that AB = 20.

By the distance formula:

AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20

4 0
3 years ago
5 - 2 (4x + 2) i need help
Fiesta28 [93]

Answer:

1-8x

Step-by-step explanation:

not sure ...........

4 0
3 years ago
Read 2 more answers
The question is in the picture
sergeinik [125]
The first one.. -12..i got you.
3 0
3 years ago
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