Thank you for posting your question here. The answer is -60.57. With appropriate sig figs it becomes -60.6 KJ.
<span>Maybe it's easier if I write what I did out: </span>
<span>2H2O > 2H2 +O2...............-H= 2* -285.83 </span>
<span>Ca + O2 + H2 > Ca(OH)2....H= -986.2 </span>
<span>2C + H2 > C2H2.................H= 226.77 </span>
<span>The above H's stand for standard enthalpy of formations. These can be found in textbook appendix. Notice the negative infront of the enthalpy (H) for H2O. This is to remind me/you that the heat lost is gained in the rxn. </span>
<span>So then you add them up. 226.77 - 986.2 + (2*285.83) = -187.77 </span>
<span>Add back the total enthalpy that is given in the question -187.77+127.2 = -60.57 </span>
<span>If signs cross you up find a way to remember that works for you. </span>
Answer:
13. Na 14. Ne. 15. U. 16. Ca. 17. C. l 18. O. 19. Cl. 20. Si 21. U 22. N.
23. Na 24. Ne. 25. U 26. Sc. 27. N 28. O 29. Cl 30. Si 31. U 32. N.
Explanation:
The general trend as you go to the right in any one period is for the size to decrease.
The general trend is that the size increases as you go down a Group.
The general trend as you go from the bottom left to the top right is a decrease in size.
Ionization energy increases as we move to the right in a period.
It decreases as we move down a group.
Going from the bottom left to top right - the ionization increases.
The reason why is because particles are moving faster and possess greater kinetic energy due to the increase in temperature, this causes greater frequency or number of collisions to take place and also allows for a higher likelihood that upon reactant molecules colliding they will undergo the reaction process as they will have achieved the required energy needed for the reaction to start. Thus overall having a greater change in quantity conversion of reactants to products within a shorter period of time, thus increasing the reaction rate.
Answer:
Sodium citrate is a compound with a total of 21 atoms