Before I answer your question, what does "dm3" means?
Your answer should be 6.4 if you attempt to solve this. I hope this helps your question!
Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125
Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50. #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5
If I’m correct, then the answer is D. Someone please correct me if I’m wrong.