All categories

2 years ago

Determine the relationship between the two triangles and whether or not they can be proven to be congruent.

Mathematics

1 answer:

Levart [38]2 years ago

8 0

Answer:

- ASA stands for "angle, side, angle" and means that we have two triangles where we know two angles and the included side are equal.

- If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

Step-by-step explanation:

You might be interested in

1) Calcule:

Margarita [4]

This is the degree other do like as that

8 0

2 years ago

Lol anyone wanna be friends

Soloha48 [4]

Answer:

Me.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

I want to make sure that my work is correct so if possible can someone look at it and tell me if i got the table part correct?

sergejj [24]

By the looks of it, it looks like you got the table correct because all of the statements match up with the graph.

7 0

2 years ago

Prove identity trigonometric equation

irina [24]

Explanation:

The given equation is False, so cannot be proven to be true.

Perhaps you want to prove ...

$2\tan{x}=\dfrac{\cos{x}}{\csc{(x)}-1}+\dfrac{\cos{x}}{\csc{(x)}+1}$

This is one way to show it:

$2\tan{x}=\cos{(x)}\dfrac{(\csc{(x)}+1)+(\csc{(x)}-1)}{(\csc{(x)}-1)(\csc{(x)}+1)}\\\\=\cos{(x)}\dfrac{2\csc{(x)}}{\csc{(x)}^2-1}=2\cos{(x)}\dfrac{\csc{x}}{\cot{(x)}^2}=2\dfrac{\cos{(x)}\sin{(x)}^2}{\cos{(x)}^2\sin{(x)}}\\\\=2\dfrac{\sin{x}}{\cos{x}}\\\\2\tan{x}=2\tan{x}\qquad\text{QED}$

We have used the identities ...

csc = 1/sin

cot = cos/sin

csc^2 -1 = cot^2

tan = sin/cos

4 0

2 years ago

A. - (3 points) Calculate the mean, median, and mode of the college professors' ages.

Anna71 [15]

I could better help if I knew the question.....

7 0

2 years ago

Determine the relationship between the two triangles and whether or not they can be proven to be congruent.​

Determine the relationship between the two triangles and whether or not they can be proven to be congruent.