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enot [183]
3 years ago
8

Solve the equation on the interval [0, 2π). tan^2x sin x = tan^2x

Mathematics
1 answer:
yulyashka [42]3 years ago
8 0
Start by getting everything on the same side of the equals sign and then set it equal to 0.  tan^2xsinx-tan^2x=0.  Factor out the common tan^2x like this: tan^2x(sinx-1)=0.  Now we have 2 separate equations to solve: tan^2x=0 and sinx = 0.  Now we have to figure out where tan^2 is 0 between 0 and 2pi.  If we include 2pi, the solutions for that equation are x = 0,  \pi , 2 \pi.  You can test those out on your calculator just to be sure.  There's only one value of x for the next equation.  The only place between 0 and 2pi where the sin x = 1 is at x = \frac{ \pi }{2}.  And there you go!
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For the given situation we have a total of 259,459,200 permutations.

<h3>How many permutations are?</h3>

First, how we know that it is a permutation?

Because the order matters, we aren't only selecting 8 out of the 15 people, but these 8 selected also have an order (is not the same thing to finish the race first than fourth, for example).

Then we need to find the number of permutations, to do it, we need to find the numbers of options for each of the 8 positions.

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Then the total number of permutations (product between the numbers of options) is:

P = 15*14*13*12*11*10*9*8 = 259,459,200

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It is given that the ΔPQR is similar to ΔPTS. It means all corresponding angles are same.

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Angle P can be defined as

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