Sean Gunn <span>plays Kirk from Gilmore Girls :) </span>
Answer:
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the number of bottles and cans:");
int numberOfbottles = in.nextInt();
int numberOfcans = in.nextInt();
System.out.printf("Bottles: %8d\n", numberOfbottles);
System.out.printf("Cans: %8d\n", numberOfcans);
}
}
Explanation:
Ask user to input the number of bottles and cans using Scanner class
Print the results so that the numbers to the right line up (Since we know that the numbers have at most 8 digits, we can use %8d in printf. Also, be aware that how printf statements are written so that the numbers line up)
He was brainliest BEFORE I answer it, so that needs an explanation
Group of answer choices.
a. firewalls
b. access controls
c. proxy servers
d. All of the above
Answer:
d. All of the above
Explanation:
Cyber security can be defined as a preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.
Generally, redundancy to prevent unauthorized access can be implemented at a number of points throughout the security architecture, such as in firewalls, proxy servers and access controls.
A firewall is a network security protocol that monitors and controls inbound and outbound traffic based on set aside security rules.
Generally, a firewall is used to control access to a computer or network, as it creates a barrier between a computer or a network and the internet in order to protect against unauthorized access. It is a security system pre-installed on most computers to essentially inspect data being transmitted to or from a computer.
An access control can be defined as a security technique use for determining whether an individual has the minimum requirements or credentials to access or view resources on a computer by ensuring that they are who they claim to be.
Simply stated, access control is the process of verifying the identity of an individual or electronic device.
Answer:
The location of both ball and the dolphin is same i.e 2.5 m above at the time 0.57 seconds this indicates that the ball and dolphin will meet.
Explanation:
As the complete question is not visible, therefore, the question is searched online and following reference question is obtained and is attached as the attachment.
From the reference question data is as follows
initial speed of the dolphin=![v_i=12 m/s](https://tex.z-dn.net/?f=v_i%3D12%20m%2Fs)
The angle at which the dolphin leaves the water is calculated as
![tan \alpha= \frac{h}{d}\\ =\frac{4.10}{5.50} = 0.745\\\alpha=tan^{-1}(0.745) = 36.7\º](https://tex.z-dn.net/?f=tan%20%5Calpha%3D%20%5Cfrac%7Bh%7D%7Bd%7D%5C%5C%20%3D%5Cfrac%7B4.10%7D%7B5.50%7D%20%3D%200.745%5C%5C%5Calpha%3Dtan%5E%7B-1%7D%280.745%29%20%3D%2036.7%5C%C2%BA)
The x and y components of initial velocity are given as
![v_i_x=v_i cos \alpha=12*cos 36.7\º = 9.62 m/s\\v_i_y=v_i sin \alpha=12*sin 36.7\º = 7.17m/s](https://tex.z-dn.net/?f=v_i_x%3Dv_i%20cos%20%5Calpha%3D12%2Acos%2036.7%5C%C2%BA%20%3D%209.62%20m%2Fs%5C%5Cv_i_y%3Dv_i%20sin%20%5Calpha%3D12%2Asin%2036.7%5C%C2%BA%20%3D%207.17m%2Fs)
Time to complete the horizontal distance by the dolphin is calculated as
![S=v_i_x \times t\\t=\frac{S}{v_i_x}\\t=\frac{5.5}{9.62}\\t=0.57 s](https://tex.z-dn.net/?f=S%3Dv_i_x%20%5Ctimes%20t%5C%5Ct%3D%5Cfrac%7BS%7D%7Bv_i_x%7D%5C%5Ct%3D%5Cfrac%7B5.5%7D%7B9.62%7D%5C%5Ct%3D0.57%20s)
Now the vertical position of ball at this instant is given as
![y_{dolphin} = v_i_y \times t-g\frac{t^2}{2}\\y_{dolphin}= 7.7 \times 0.57-10\frac{0.57^2}{2}\\y_{dolphin}=2.5 m](https://tex.z-dn.net/?f=y_%7Bdolphin%7D%20%3D%20v_i_y%20%5Ctimes%20t-g%5Cfrac%7Bt%5E2%7D%7B2%7D%5C%5Cy_%7Bdolphin%7D%3D%207.7%20%5Ctimes%200.57-10%5Cfrac%7B0.57%5E2%7D%7B2%7D%5C%5Cy_%7Bdolphin%7D%3D2.5%20m)
Now the location of ball at the instant is given as
![y_{ball}=y_{ball-o}+v_i_y_{ball} \times t-g\frac{t^2}{2}\\y_{ball}=4.1+0 \times 0.57-10\frac{0.57^2}{2}\\y_{ball}=2.5 m](https://tex.z-dn.net/?f=y_%7Bball%7D%3Dy_%7Bball-o%7D%2Bv_i_y_%7Bball%7D%20%5Ctimes%20t-g%5Cfrac%7Bt%5E2%7D%7B2%7D%5C%5Cy_%7Bball%7D%3D4.1%2B0%20%5Ctimes%200.57-10%5Cfrac%7B0.57%5E2%7D%7B2%7D%5C%5Cy_%7Bball%7D%3D2.5%20m)
<em>As the location of both ball and the dolphin is same i.e 2.5 m above at the time 0.57 seconds this indicates that the ball and dolphin will meet.</em>
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