Answer: last option
Step-by-step explanation:
To solve this problem you must apply the properties of the exponents. WHen you have two powers with equal base, you must add the exponents.
Then you have:
![(6a^{2}b^{3})(-3a^{5}b^{3})=-18a^{(2+5)}b^{(3+3)}=-18a^{7}b^{6}](https://tex.z-dn.net/?f=%286a%5E%7B2%7Db%5E%7B3%7D%29%28-3a%5E%7B5%7Db%5E%7B3%7D%29%3D-18a%5E%7B%282%2B5%29%7Db%5E%7B%283%2B3%29%7D%3D-18a%5E%7B7%7Db%5E%7B6%7D)
Therefore as you can see, the coefficient is -18
Answer:
Step-by-step explanation:
<u>Use properties of rhombus:</u>
- diagonals are perpendicular
- diagonals are angle bisectors
- opposite angles are equal
<u>The angle measures are:</u>
- m∠2 = 90°
- m∠3 = 70°
- m∠1 = m∠4 = 90° - 70° = 20°
In step 1, the commutative property of addition is used since x + 5 is just equal to 5 + x
In step 2, the associative property of addition is used since x is grouped to the last term.
In step 3, the distributive property of multiplication is used since 3 is multiplied to the terms inside the parenthesis.
In step 4, multiplication is done.
If this shape is trapezium
m (<D) = m (<C)
since AB parallel to CD
m (<C) + m (<A) = 180°
m (<C) = 180 - 125 = 55°
m (<D) = 55°
mark me as brainlest, please