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Angelina_Jolie [31]
4 years ago
9

A fish jumps out of the water at a speed of 12 feet per second. The height y (in feet) of the fish above the surface of the wate

r is represented by the equation y=-16x^2+12x, where x is the time (in seconds) since the jump began. The fish reaches its highest point above the surface of the water after 0.375 seconds. How far above the surface is the fish at this time?
Mathematics
1 answer:
sasho [114]4 years ago
8 0

Answer:

The fish is 2.25 ft above the surface at 0.375 seconds

Step-by-step explanation:

Given:

y=-16x^2+12x

x=0.375 seconds

Substitute x=0.375 into the equation

y=-16x^2+12x

= -16(0.375)^2 +12(0.375

= -16(0.140625) + 4.5

= -2.25 + 4.5

= 2.25

y=2.25 ft

The fish is 2.25 ft above the surface at 0.375 seconds

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The area of the square is 100 square centimeters. What is the area of the circle?
swat32

Answer:

  • Since the question is incomplete, see the figure attached and the explanation below.

Explanation:

Since the figure is missing, I enclose the figure of a square inscribed in a circle.

Since the <em>area of a square</em> is the side length squared, you can determine the side length:

  • Area = (side length)²
  • 100 cm² = (side lenght)²

        side\text{ }length=\sqrt{100cm^2}=10cm

From the side length, you can find the diagonal of the square, which is equal to the diameter of the circle, using the Pythagorean theorem:

  • diagonal² = (10cm)² + (10cm)² = 2 × (10cm)²

         diagonal=\sqrt{2\times (10cm)^2}\\ \\ diagonal=10\sqrt{2} cm

The area of the circle is π (radius)².

  • radius = diameter/2 = diagonal/2

        area= \pi \times (5\sqrt{2}cm)^2=50\pi cm^2

6 0
3 years ago
Please help me:(I’ll give you the brainliest
Savatey [412]

Answer:

The range of values for x is; 5 < x < 29

Step-by-step explanation:

The given parameters are;

\overline {AB} = 15

\overline {AD} = 18

\overline {BC} = \overline {CD} Given

\overline {AC} = \overline {AC} by reflexive property

∠BCA = 2·x - 10

∠DCA = 48°

Since 15 < 18, given the common sides of the tringle ΔABC and triangle ΔADC, angle ∡(2·x - 10)° < 48°

Therefore;

2x - 10 < 48

2·x < 48 + 10

∴ x < 29

Also, given that 2·x - 10 is real, 0 < 2·x - 10

10 < 2·x

10/2 < x

5 < x

Therefore, an acceptable range is 5 < x < 29

4 0
3 years ago
0.2,-0.6,1/2,-2/3,5/8 in order from least to greatest using a number line
Neko [114]

Answer:

-2/3, -0.6, 0.2, 1/2, 5/8

Step-by-step explanation:

What you do is you have to make them into decimals.

-0.6 and 0.2 are already in decimals.

-2/3 as a decimal is -0.667

1/2 as a decimal is 0.5

5/8 as a decimal is 0.625

-2/3, -0.6, 0.2, 1/2, 5/8 is your answer.

8 0
3 years ago
H(n) = -10 + 12n<br> Complete the recursive formula of h(n).<br> h(1) =<br> h(n) = h(n-1)+
OlgaM077 [116]

Answer:

h(n) = h(n - 1) + 12

Step-by-step explanation:

Generate the first few terms using the explicit formula

h(1) = - 10 + 12 = 2

h(2) = - 10 + 24 = 14

h(3) = - 10 + 36 = 26

h(4) = - 10 + 48 = 38

This is an arithmetic sequence. To find a term in the sequence add 12 to the previous term, thus

h(n) = h(n - 1) + 12 with h(1) = 2

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3 years ago
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