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VARVARA [1.3K]
3 years ago
15

Someone pls help me I will make you brain

Mathematics
2 answers:
Pani-rosa [81]3 years ago
4 0
The last one you just have to plug 1 and 3 into the given equation
Vikentia [17]3 years ago
3 0

It cannot be compared, so answer 3 :)

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If sin A = 6 over 13, then which of the following is correct?
Inessa [10]
Answer is B. CSC A= 13 over 6
You need to learn these basic rules:
Sin is opposite csc
Cos is opposite sec
Tan is opposite Cot
In saying this, CsC is the reciprocal for Sin. You would have to switch the numerator and denominatior to get your answer
4 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!
Gre4nikov [31]

Answer:

Explanation below.

Step-by-step explanation:

1. a. \sqrt{x} =12

  b. \sqrt{x} ^{2}=12^{2}

  c. x=144

2. a. \sqrt{x^{2} } =\sqrt{196}

   b. x= 14

3.  

\sqrt{x} -4 +4= 8+4\\\sqrt{x} =12\\x= 3.46410161514  \\or  \\2\sqrt{3}

4.

2(x^{2} +3)=398\\x^{2} +3= 199\\x^{2} =196\\x=14

7 0
3 years ago
Read 2 more answers
A bag contains n blue and m red marbles. You randomly pick a marble from the bag, write down its color, and then put the marble
Oksana_A [137]

Answer:

(mn+n²)/(m+n)

Step-by-step explanation:

probability of blue marble= n/(n+m)

probability of red marble= m/(n+m)

probability that process stops = Probability of both blue + probability of both red=  n/(n+m) × n/(n+m) + m/(n+m)×m/(n+m)

                        = (n²+m²)/(n+m)²

P(1st marbel is blue)= P(blue and red) + P(blue and blue)

                                  = mn/(n+m) + n²/(n+m)

                                   = (mn+n²)/(m+n)

P(1st marble is blue | process stops)= ( (mn+n²)/(m+n)× (n²+m²)/(n+m)²)/ ((n²+m²)/(n+m)²)

= (mn+n²)/(m+n)

3 0
3 years ago
Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.
k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = \frac{3}{4},

q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28

       = 6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28

       = (\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28

       = (\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}

       = -\frac{1666}{64}

       = -\frac{833}{32} ≠ 0

Therefore, Yuri is not correct. x = \frac{3}{4} can not be a root of the given expression.

6 0
3 years ago
Read 2 more answers
How can you check your answer in unit rates?
muminat

Answer:

<h3>⭐In a unit rate, the denominator is always 1. So, to find unit rate, divide the denominator with the numerator in a way that the denominator becomes 1. For example, if 50km is covered in 5.5 hours, the unit rate will be 50km/5.5 hours = 9.09 km/hour.</h3>

Step-by-step explanation:

<h2>⛄I hope it's helpful for you ⛄</h2>
6 0
3 years ago
Read 2 more answers
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