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Kruka [31]
3 years ago
8

Multiply the following and simplify.

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0
What are we multiplying exactly?
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The rectangle shown has a perimeter of 7272 cm and the given area. its length is 66 more than four timesfour times its width. wr
Vadim26 [7]
<span>Width = 6 Length = 30 We know the perimeter of a rectangle is simply twice the sum of it's length and width. So we have the expression: 72 = 2*(L + W) And since we also know for this rectangle that it's length is 6 more than 4 times it's width, we have this equation as well: L = 6 + 4*W So let's determine what the dimensions are. Since we have a nice equation that expresses length in terms of width, let's substitute that equation into the equation we have for the perimeter and solve. So: 72 = 2*(L + W) 72 = 2*(6 + 4*W + W) 72 = 2*(6 + 5*W) 72 = 12 + 10*W 60 = 10*W 6 = W So we now know that the width is 6. And since we have an expression telling us the length when given the width, we can easily determine the length. So: L = 6 + 4*W L = 6 + 4*6 L = 6 + 24 L = 30 And now we know the length as well.</span>
5 0
3 years ago
Over what interval is the growth rate of the function decreasing?
aleksklad [387]
I think the rate is decreasing from:
(-infinity, ln9/3)
6 0
3 years ago
Sean reads 1 1/2 pages in 3 1/3 minutes. What is his average page per minute?
Helga [31]

Answer:

9/20 pages per minute.

Step-by-step explanation:

4 0
3 years ago
Write the equation of a parabola whose focus is at (-7, 3) and whose directrix is the line x = -3.
Sav [38]

Check the picture below.

now, let's keep in mind that, the vertex is half-way between the focus point and the directrix, it's a "p" distance from each other.

since this horizontal parabola is opening to the left-hand-side, "p" is negative, notice in the picture, "p" is 2 units, and since it's negative, p = -2.

its vertex is half-way between those two guys, so that puts the vertex at (-5, 3)

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=7\\ p=-2 \end{cases}\implies 4(-2)[x-(-5)]=[y-7]^2 \\\\\\ -8(x+5)=(y-7)^2\implies x+5=\cfrac{(y-7)^2}{-8}\implies \boxed{x=-\cfrac{1}{8}(y-7)^2-5}

7 0
4 years ago
How do u do #10? Plz show on paper
Studentka2010 [4]
Reflection across the line y=x simply swaps the x and y coordinates.
K'(-2, -5), A'(1, -4), I'(-1, 0), J'(-4, -2)

3 0
3 years ago
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