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3 years ago

Largest common multiple for 2 and 3?

Mathematics

2 answers:

nydimaria [60]3 years ago

5 0

Answer:

Step-by-step explanation:

natulia [17]3 years ago

4 0

Answer:

24 i think

Step-by-step explanation:

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Pleaseeeee pleaseeee helppppppppp

telo118 [61]

Given:

The two vectors are:

$\overrightarrow{a}=2\hat{i}-\hat{j}+\hat{k}$

$\overrightarrow{b}=\hat{i}-3\hat{j}+5\hat{k}$

To find:

The value of $|\overrightarrow{a}\times \overrightarrow{b}|$ .

Solution:

We have,

$\overrightarrow{a}=2\hat{i}-\hat{j}+\hat{k}$

$\overrightarrow{b}=\hat{i}-3\hat{j}+5\hat{k}$

The cross product of these two vectors is:

$\overrightarrow{a}\times \overrightarrow{b}=\begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\2&-1&1\\1&-3&5\end{vmatrix}$

$\overrightarrow{a}\times \overrightarrow{b}=\hat{i}[(-1)(5)-(1)(-3)]-\hat{j}[(2)(5)-(1)(1)]+\hat{k}[(2)(-3)-(-1)(1)]$

$\overrightarrow{a}\times \overrightarrow{b}=\hat{i}[-5+3]-\hat{j}[10-1]+\hat{k}[-6+1]$

$\overrightarrow{a}\times \overrightarrow{b}=-2\hat{i}-9\hat{j}-5\hat{k}$

Now the magnitude of the cross product is:

$|\overrightarrow{a}\times \overrightarrow{b}|=\sqrt{(-2)^2+(-9)^2+(-5)^2}$

$|\overrightarrow{a}\times \overrightarrow{b}|=\sqrt{4+81+25}$

$|\overrightarrow{a}\times \overrightarrow{b}|=\sqrt{110}$

Therefore, the value of $|\overrightarrow{a}\times \overrightarrow{b}|$ is $\sqrt{110}$ .

5 0

3 years ago

Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1

harkovskaia [24]

$y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\
y''(0)=20\cdot0^3=0$

The value of the second derivative for $x=0$ is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of $5x^4$ is always positive for $x\in\mathbb{R}\setminus \{0\}$ . That means at $x=0$ there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval $[-2,1]$ .
The function $y$ is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

$y_{max}=y(1)=1^5-3=-2$

4 0

3 years ago

Solve the system of equations <br> 5x-7y=58<br> y=-x+2

Darya [45]

Here is your answer
Please mark it brainliest !!