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3 years ago

Hellooooooo I need help with this !!!!!

Mathematics

1 answer:

Leviafan [203]3 years ago

5 0

Answer:

c. 270m^3

Step-by-step explanation:

To find the volume of a rectangular prism, multiply its 3 dimensions: length x width x height.

6×5×9

30×9

270

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A researcher is interested in looking at a new type of insulin that can treat diabetics with high fasting glucose levels. Suppos

Makovka662 [10]

Answer:

The sample size should be at least 79.

Step-by-step explanation:

Let Y be be the resting glocose level of a member of the population chosen randomly, then Y is a random variable with unkown mean λ and Standard deviation σ = 27.

Let X be the sample mean of a sample of lenght n. X has the same mean as Y and the standard deviation is $\sigma = \frac{27}{\sqrt{n}} .$

If n is reasonable high, the Central Limit Theorem states that X has distribution approximately Normal, with mean λ and Standard deviation $sigma = \frac{27}{\sqrt{n}} .$

If we standarize X, we get a random variable W

$W = \frac{X-\lambda}{\frac{27}{\sqrt{n}}} \simeq N(0,1)$

The values of W are tabulated and can be found on the attached file. We want a 95% confidence interval, so we want Z such that

P(-Z < w < Z) = 0.95

Using the symmetry of the normal density function, we get that

P(W < Z) = 0.975

If we look at the table, we will find that Z = 1.96, therefore we have

$P(-1.64 < \frac{X-\lambda}{\frac{27}{\sqrt{n}}} < 1.64) = 0.95$

Equivalently,

$0.95 = P(-1.64*\frac{27}{\sqrt{n}} < X- \lambda < 1.64*\frac{27}{\sqrt{n}})$

Taking out the X and the sign, after reverting the inequalities, we obtain

$P(X -1.64*\frac{27}{\sqrt{n}} < \lambda < X +1.64*\frac{27}{\sqrt{n}}) = 0.95$

Thus, a confidence interval with 95% confidence is

$CI = [ X-1.64*\frac{27}{\sqrt{n}}, X+1.64*\frac{27}{\sqrt{n}}]$

The (absolute) margin of error of this interval is $1.64*\frac{27}{\sqrt{n}} ,$ we want that number to be at most 5, so we take n such that

$1.64*\frac{27}{\sqrt{n}} = 5 \, \rightarrow \frac{1}{\sqrt{n}} = \frac{5}{1.64*27} \, \rightarrow \sqrt{n} = 8.85 \, \rightarrow n = 78.42$

We take n = 79. I hope that works for you!

Download pdf

4 0

3 years ago

If b√2 = 6, what does b equal? I don't know why I'm stuck on this problem, but could somebody help me?

kotegsom [21]

Answer:

Step-by-step explanation:

Divide both sides by the square root of 2. If you are looking for an exact answer that is rationalized, it would be found by multiplying 6/sqrt(2) * sqrt(2)/sqrt(2) to get

$b=\frac{6\sqrt{2} }{2}=3\sqrt{2}$

8 0

3 years ago

Read 2 more answers

Please help!! I’m in algebra 1 and I’m confuseddddd bruh help me please

Grace [21]

Answer:

n = 4

Step-by-step explanation:

$\sqrt[n]{256} = 8^{1/3} * 8^{1/3}$

$\sqrt[n]{256} = 8^{2/3}$

$\sqrt[n]{2^8} = 8^{2/3}$

$2^{8/n} = 2^{3 * (2/3)}$

$2^{8/n} = 2^{2}$

$8/n = 2$

$2n = 8$

$n = 4$ < --- This is your answer

Hope this helps!

7 0

4 years ago

A bakery sells cakes for $23 And a dozen cupcakes for $18. In one day they sold 72 items and made a total of $1446. Which system

katrin2010 [14]

Answer:

23c+18x=1446

Step-by-step explanation:

3 0

3 years ago

can someone help me simplify this: the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the th

VMariaS [17]

10x^6y^3 + 20x^3y^2 / 5x^3y =
5x^3y (2x^3y^2 + 4y) / 5x^3y=
<span>2x^3y^2 + 4y
</span>
First you find what the expressions 10x^6y^3 and 20x^3y^2 have in common, and that is 5x^3y, which is the same as the denominator, so you can easily divide them and get 1.
<span>Hope you understand!

</span>

8 0

4 years ago