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Artyom0805 [142]
2 years ago
8

A long paper strip with a width of 5 cm is folded, as shown in the picture. Find the smallest possible area of the gray triangle

that is formed after folding.

Mathematics
1 answer:
Stolb23 [73]2 years ago
3 0

By using some logic and the formula of the triangle's area, we will find that the smallest possible area is 12.5 cm²

How to start thinking about the problem.

First of all, for the configuration of this paper strip, we can see that the base of the triangle will <u>always be equal of the width of the paper</u>. Thus, the smallest area will be only dependent of the height of the triangle.

Now, we need to analyze the picture to figure out how we can get the smallest height possible for that triangle.

What is the smallest height possible.

Doing this, we shall see that the smallest height possible is actually when the height equals the width itself, as it's shown in the attached image.

How to calculate the smallest area possible.

Thus, to calculate the smallest area, we just have to use the formula of the area of the triangle, which is   \frac{b\times h}{2}<em>, where </em><u><em>b is the base</em></u><em> and </em><u><em>h is the height</em></u><em>.</em>

As we previously found, for this question, the

<em>base = height = width of the paper = 5cm</em>

Now, we just have to calculate it with the formula

Area = \frac{base \times height}{2} \\\\&#10;\\&#10;Area = \frac{5 \times 5}{2} \\&#10;\\&#10;Area = \frac{25}{2}\\&#10; \\&#10;Area = 12.5 cm^{2}

learn more about the area of the triangle here: brainly.com/question/15442893

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MakcuM [25]

Option C

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<em><u>Solution:</u></em>

Given that we have to simplify the expression shown below

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Let us first convert 0.00048 to scientific notation

<em><u>Steps to follow:</u></em>

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is a.

Count how many places you moved the decimal point. This number is b.

If you moved the decimal to the left b is positive.

If you moved the decimal to the right b is negative.

If you did not need to move the decimal b = 0.

Write your scientific notation number as a x 10^b and read it as "a times 10 to the power of b."

Remove trailing 0's only if they were originally to the left of the decimal point.

0.00048 = 4.8 \times 10^{-4}

So the given expression becomes,

\rightarrow 4.8 \times 10^{-4} - 3.4 \times 10^{-5}

Let us make the exponent of second term as -4

\rightarrow 4.8 \times 10^{-4} - 0.34 \times 10^{-4}

Take 10^{-4} as common term,

\rightarrow 10^{-4} (4.8 - 0.34)

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Thus option C is correct

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