The transformations that would prove that circles A and C are similar are:
- A. Reflect A over the line y=x
- C. Dilate A by 3/2
<h3>How to prove that circle A and circle C are similar?</h3>
The circles are given as:
Circle A and B
Assume the following parameters:
- The center of circle A is (2,3) with a radius of 2
- The center of circle B is (3,2) with a radius of 3
To start with;
The circle A must be reflected across the line y = x with the following transformation rule:
(x,y) -> (y,x)
So, we have:
(2,3) -> (3,2)
Next, the radius of A must be dilated by 3/2 as follows:
New Radius = 3/2 * 2 = 3
After the transformations, we have the following parameters:
- The center of circle A is (3,2) with a radius of 3
- The center of circle B is (3,2) with a radius of 3
Notice that both circles now have the same center and radius.
Hence, both circles are similar
Read more about similar circles at:
brainly.com/question/9177979
Answer
-2/2
Step-by-step explanation:
Answer:
![[x - 1][x + 1][{x}^{2} + 4]](https://tex.z-dn.net/?f=%5Bx%20-%201%5D%5Bx%20%2B%201%5D%5B%7Bx%7D%5E%7B2%7D%20%2B%204%5D)
Step-by-step explanation:
Knowing that you have to find two numbers that when they differ to 3, they also multiply to −4, and those numbers are −1 and 4. So, after clearing that up, you will have this [since our degree of this polynomial function is 4]:
![[{x}^{2} - 1][{x}^{2} + 4]](https://tex.z-dn.net/?f=%5B%7Bx%7D%5E%7B2%7D%20-%201%5D%5B%7Bx%7D%5E%7B2%7D%20%2B%204%5D)
Then, since 
is factorable, you will get this:
![[x - 1][x + 1]](https://tex.z-dn.net/?f=%5Bx%20-%201%5D%5Bx%20%2B%201%5D)
Finally, attach ![[{x}^{2} + 4]](https://tex.z-dn.net/?f=%5B%7Bx%7D%5E%7B2%7D%20%2B%204%5D)
to the partially factored polynomial to get this:
I am joyous to assist you anytime.
Answer:
5
Step-by-step explanation:
ITS 5
Answer:
I think 4
Step-by-step explanation:
Red hat costs $32
black hat costs $8
32 (divided) by 8 is 4
