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Zarrin [17]
3 years ago
5

(b) Lashonda's test score average increased by 12 points this semester.

Mathematics
1 answer:
sukhopar [10]3 years ago
8 0

9514 1404 393

Answer:

  +12

Step-by-step explanation:

An increase is generally represented by a positive number. An increase of 12 points will usually be represented by the number +12.

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As a store manger you would like to find out the average time it takes to unload the truck which delivers the merchandise for yo
Georgia [21]

Answer:

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

Step-by-step explanation:

We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 35 - 1 = 35

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.975([tex]t_{975}). So we have T = 2.0322

The margin of error is:

M = T*s = 2.0322*30 = 60.97

The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

4 0
3 years ago
Read 2 more answers
Please help again, sorry for asking…
prohojiy [21]

Answer:

BC=6x+4= 6x4+4 = 28 is the correct answer

AB+BC=AC

4x+8+6x+4=52

10x+12=52

10x=40

X=4

4 0
3 years ago
Read 2 more answers
Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0
2 years ago
If you were to create a histogram from the data shown in the stem-and-leaf plot, with each bar covering six values from 13 to 42
snow_tiger [21]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the 40th term of the arithmetic sequence 13, 26, 39, 52
Diano4ka-milaya [45]

Answer:

your answer would be 520

Step-by-step explanation:

13 x 40 = 520

7 0
2 years ago
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