Answer:
y=x-1
Step-by-step explanation:
<h3>
Answer: 3 m/s^2</h3>
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According to Newton's Second Law, we know that
F = m*a
where F is the force applied, m is the mass and 'a' is the acceleration.
We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.
Plug in F = 35 and a = 5 to find m
F = ma
35 = m*5
35/5 = m
7 = m
m = 7
The object has a mass of 7 kg
Our equation F = ma updates to F = 7a
Now plug in the force F = 21 to find 'a'
F = 7a
21 = 7a
21/7 = a
3 = a
a = 3
The acceleration will be 3 m/s^2
Notice how a smaller force applied means that the acceleration has also gone down as well.
Answer:
JK = 42 , KL = 78
Step-by-step explanation:
JK + KL = JL , substitute values
4x + 6 + 7x + 15 = 129 , that is
11x + 21 = 120 ( subtract 21 from both sides )
11x = 99 ( divide both sides by 11 )
x = 9
Then
JK = 4x + 6 = 4(9) + 6 = 36 + 6 = 42
KL = 7x + 15 = 7(9) + 15 = 63 + 15 = 78
Answer:
$220
Step-by-step explanation:
5.50 ÷ 10 = .550
$.40 x 550 = $220
There may be more than one way in which to answer this question. I will assume that the "equation" is a linear one: f(x) = mx + b.
Then (16/3) = m(1) + b
This is one equation in two unknowns, so it does not have a unique solution. Was there more to this problem than you have shared?
If we assume that the y-intercept (b) is zero, then y = mx, and
16/3 = 1m, so that m = 16/3, and so y = (16/3)x.
