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andreyandreev [35.5K]
3 years ago
15

Help asap i will give brainliest!!!!!

Mathematics
2 answers:
Oksanka [162]3 years ago
8 0

1.) slope: -4 (m = -4)

2.) slope: 0 (m = 0)

3.) slope: undefined (infinite)

4 & 5 are pictured below:)

hope this helps!

Hoochie [10]3 years ago
4 0

Answer:

BRO U GO TO RSM!!!!!! i got u i think i did that read the comments

Step-by-step explanation:

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Please Help! WILL MARK BRAINLIEST! The question is in the picture. Thanks!
Sonbull [250]

Answer:

third option: (x+3) / √x+2

Step-by-step explanation:

f(x) = √x+2           g(x) = (x² + 1) / x

(g·f)(x) = g(f(x)) = ((√x+2)² + 1) / √x+2

==> (x+2+1) / √x+2

==> (x+3) / √x+2

5 0
3 years ago
Your salary is $65,788. If you work fifth 40-hour weeks in a year, what is your hourly wage?
vampirchik [111]
Omggggg are you cereals
7 0
3 years ago
A father is 3 times as old as his son and his daughter is 3 years younger than the son. Fi the sum of there ages 3 years ago was
inn [45]

Answer:the present age of the father is 45 years

Step-by-step explanation:

Let x represent the present age of the father.

Let y represent the present age of the son.

Let z represent the age of the daughter.

A father is 3 times as old as his son. This means that

x = 3y

his daughter is 3 years younger than the son. It means that

z = y - 3

The sum of their ages 3 years ago was 63. This means that

x - 3 + y - 3 + z - 3 = 63

x + y + z - 9 = 63 - - - - - - - - - - 1

Substituting x = 3y and z = y - 3 into equation 1, it becomes

3y + y + y - 3 - 9 = 63

5y - 12 = 63

5y = 63 + 12 = 75

y = 75/5 = 15

x = 3y = 3 × 15

x = 45

z = y - 3 = 15 - 3

z = 12

3 0
3 years ago
The weather was a youth soccer field must be at least 45 m but it cannot exceed 60 m right to inequalities that describe the wid
ss7ja [257]

Answer:

The width of the two soccer field must be given by 45\leq w\leq 60.

Assuming two Integers that are solutions of both inequalities are 45 and 60.

Step-by-step explanation:

Let the width of the youth soccer field be 'w'.

Now Given:

the width of the youth soccer field must be at least 45 m.

So we can say that;

w\geq 45 \ m

Also Given:

the width of the youth soccer field must not exceed 60 m.

So we can say that;

x\leq 60

Hence the width of the two soccer field must be given by 45\leq w\leq 60.

So we can say that;

Any Integer lying between integers 45 and 60 can be considered as the width of the youth soccer field.

So let us Assume two Integers that are solutions of both inequalities are 45 and 60.

7 0
4 years ago
What is the sum of 3/10s and 5/100s <br> (Fractions)
vampirchik [111]

Answer:

80/100

Step-by-step explanation:

this is simplified ones

8/10

4/5

4 0
3 years ago
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