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2 years ago

." id="TexFormula1" title="\left \{ {{a^2 -2a-b^2=0} \atop {2b+2ab=0}} \right." alt="\left \{ {{a^2 -2a-b^2=0} \atop {2b+2ab=0}} \right." align="absmiddle" class="latex-formula">
Help me solve this plsss

Mathematics

1 answer:

oksian1 [2.3K]2 years ago

8 0

Given :-

a² - 2a - b² = 0
2b + 2ab = 0

To find :-

Value of a and b .

Solution :-

Taking second equation:-

2b + 2ab = 0
2b ( 1 + a ) = 0
2b = 0 or (1+a) = 0
b = 0 , a = -1

Substitute in first equation :-

a² - 2a - b² = 0

When b = 0 ,

a² - 2a - 0² = 0
a² - a = 0
a( a -1) =0
a = 0 , 1

When a = -1 ,

(-1)² - 2*(-1) - b² = 0
1 + 2 - b² = 0
b² = 3
b = ±√3

Answer :-

a = 0,1 ; b = 0
a = -1 , b = ±√3

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