Hey there!
If two angles are supplementary, that means that the measures of the two angles have a sum of 180.
If the two angles were of equal measure, they would both be 90 degrees.
The easiest way to get this would be to subtract 12 degrees from one 90 degree angle and add them to the other 90 degree angle so one angle has 24 more degrees then the other.
90 - 12 = 78
90 + 12 = 102
Let's check to make sure this works.
102 + 78 = 180 That checks out.
102 - 24 = 78 That also works.
So, the measures of the angles are 102 and 78.
Hope this helps!
We know that
The triangle inequality<span> states that for any </span>triangle, t<span>he sum of the lengths of any two sides of a </span>triangle<span> is greater than the length of the third side
</span>so
case <span>A. 81 mm, 7 mm, 6 mm
6+7 is not > 81
case </span><span>B. 81 mm, 7 mm, 72 mm
72+7 is not > 81
case </span><span>C. 81 mm, 7 mm, 88 mm
81+7 is not > 88
case </span><span>D. 81 mm, 7 mm, 77 mm
81+7 is > 77------> ok
77+7 is > 81-----> ok
81+77 is > 7-----> is ok
the answer is the option
</span>D. 81 mm, 7 mm, 77 mm
Choose values for x, multiply them by 2, then graph these points.<span />
Answer:
Part 1) The length of the diagonal of the outside square is 9.9 units
Part 2) The length of the diagonal of the inside square is 7.1 units
Step-by-step explanation:
step 1
Find the length of the outside square
Let
x -----> the length of the outside square
c ----> the length of the inside square
we know that
step 2
Find the length of the inside square
Applying the Pythagoras Theorem
substitute
step 3
Find the length of the diagonal of the outside square
To find the diagonal Apply the Pythagoras Theorem
Let
D -----> the length of the diagonal of the outside square
step 4
Find the length of the diagonal of the inside square
To find the diagonal Apply the Pythagoras Theorem
Let
d -----> the length of the diagonal of the inside square
