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liberstina [14]
2 years ago
12

Helpppppppppppppppppppp

Mathematics
1 answer:
Elza [17]2 years ago
6 0
1.) 3.8 because 10^8 is 100,000,000. 8.4 times 100,000,000 is 840,000,000. Then, 2.2 times 1000,000,000 is 220,000,000. You divide those and get 3.8

2.) 111.111111 because 10^-4 is .001. you divide that by 9 and get .009. 10^-5 is .00001, you times that by 3.5 and get .000035 which is 111.111111

3.) 500

4.) 177.083333

5.) 30
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An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t
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Answer:

a) Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

b) Rachel, because her time had the lowest z-score.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

The lower the time, the better the runner is. So whoever's time has a lower z-score is a better runner. So initially, we find the z-score of each student's time.

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in the class, ran 1 mile in 8 minutes.

This means that for Rachel's time, we have that X = 8, \mu = 11, \sigma = 3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 11}{3}

Z = -1

A junior high school class ran 1 mile in an average of 9 minutes, with a standard deviation of 2 minutes. Kenji, a student in the class, ran 1 mile in 8.5 minutes.

This means that for Kenji's time, we have that X = 8.5, \mu = 9, \sigma = 2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.5 - 9}{2}

Z = -0.25

A high school class ran 1 mile in an average of 7 minutes with a standard deviation of 4 minutes. Nedda, a student in the class, ran 1 mile in 8 minutes.

This means that for Nedda's time, we have that X = 8, \mu = 7, \sigma = 4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 7}{4}

Z = 0.25

(a) Why is Kenji considered a better runner than Nedda, even though Nedda ran faster than he?

Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

(b) Who is the fastest runner with respect to his or her class? Explain why

Rachel, because her time had the lowest z-score.

8 0
3 years ago
Find the value of (3+4)squared
Ilya [14]
49

3+4 is 7
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6 0
2 years ago
Read 2 more answers
Karl had planned to drive for 1023 hours on a certain day during his road trip. When he became sleepy, however, he decided to de
netineya [11]

Since Karl became sleepy and decided to decrease his driving time by 25%, he drove <u>767.25 hours</u> that day.

<h3>What is driving time?</h3>

Planned driving time is the estimated time that Karl planned to drive between two points or to one's destination.

The Actual driving time is the actual time that it took Karl to drive from one point to his destination.

Driving time can be estimated or calculated by dividing the distance by the speed.

<h3>Data and Calculations:</h3>

The planned driving hours on a certain day = 1,023 hours

Decrease in driving time = 25%

Percentage of hours Karl drove = 75% (100 - 25)

Hours drove that day = 767.25 hours (1,023 x 75%)

Thus, Karl drove <u>767.25 hours</u> that day.

Learn more about driving time at brainly.com/question/4931057

#SPJ1

8 0
1 year ago
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