This is a lot of information at once, so break down the question step by step!
1) You are told that 34.6% of Mr. Camp's class of 26 students reported that they have at least 2 siblings. Find the number of students in his class that have at least two siblings by multiplying 0.346 (the decimal form of 34.6%) by 26:
0.346 x 26 = 9 students
However, be careful! Notice that you want the number of students with fewer than 2 siblings. That means you need to subtract 9 from 26 to find the number of students with less than 2 siblings:
26 - 9 = 17 students
2) You are told that there are 1800 eighth-grade classes in the state, and the average size of the classes is 26. That means you can assume that there are 1800 classes of 26 in the state.
Since you are told that Mr. Camp's class is representative of students in the state's 8th grade classes. That means in the state, for each class of 26, 17 students (the number we figured out in step 1) have fewer than two siblings!
For each of the 1800 classes of 26, 17 students have fewer than two siblings. That means you need to multiply 1800 classes by 17 students per class to get your final answer, which is answer C:
1800 x 17 = 30,600
------
Answer: C) 30,600
Answer:
y = - 24
Step-by-step explanation:
Given that y varies directly with x then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition y = 12 when x = - 3
k =
=
= - 4
y = - 4x ← equation of variation
When x = 6, then
y = - 4 × 6 = - 24
The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
<h3>What is the claim that the return rate is less than 20% by using a statistical hypothesis method?</h3>
The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:


Given that:
Sample size (n) = 6965
Sample proportion 
The test statistics for this data can be computed as:



z = -2.73
From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.
Hence, the p-value for the test statistics can be computed as:
P-value = P(Z ≤ z)
P-value = P(Z ≤ - 2.73)
By using the Excel function =NORMDIST (-2.73)
P-value = 0.00317
P-value ≅ 0.003
Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
Learn more about hypothesis testing here:
brainly.com/question/15980493
#SPJ1