To name 3 decimals between .55 and .56 just add another number to .55 For instance, .551 and .552 and
.553 are Three decimals between .55 and .56. If we start off with .55 we will not get to .56 untill .559 flips.
So
.550
.551
.552
.553
.554
.555
.556
.557
.558
.559
.56
1. 30
2. m < Q = m < S
3. 35 i think
4. Obtuse
Answer:
$43-$27=$16
Step-by-step explanation:
Answer:
to be honest i need the points so srry
Step-by-step explanation:
Compare to the series
![\displaystyle\sum_{n=1}^\infty\frac7{10n}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bn%3D1%7D%5E%5Cinfty%5Cfrac7%7B10n%7D)
which is divergent. We have
![\displaystyle\lim_{n\to\infty}\dfrac{\frac7{10n+3\sqrt n}}{\frac7{10n}}=\lim_{n\to\infty}\dfrac{10n}{10n+3\sqrt n}=1](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bn%5Cto%5Cinfty%7D%5Cdfrac%7B%5Cfrac7%7B10n%2B3%5Csqrt%20n%7D%7D%7B%5Cfrac7%7B10n%7D%7D%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%5Cdfrac%7B10n%7D%7B10n%2B3%5Csqrt%20n%7D%3D1)
Because this limit is finite and positive, the original series must also be divergent (by the limit comparison test).