The y intercept is 5, since slope is y=mx+b. The x intercept is at -2. If you have more problems like this there is an amazing calculator that graphs equations like this for you. www.symbolab.com. Hope this helps!
Answer:
D. The point at x = 0 is x-intercept itself.
Step-by-step explanation:
First, substitute x = 0 in f(x) = sin(x) and examine the point and values.
When x = 0, sin(0) = 0.
Hence, the point is (0,0) which is an origin point. It is both x-intercept and y-intercept at the same time.
The point at x = 0 is neither maximum nor minimum since the range of some function is defined in [-1,1] so the minimum value has to be -1 and the maximum value has to be 1.
Thus, A and B are not correct choices.
The C choice would make sense if the value of f(x) did not become 0 when substituting x = 0 in.
Therefore, the correct choice is D as it is an origin point at x = 0 meaning it is both x-intercept and y-intercept.
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Answer:
50 Pick me brainliest
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u><em>(1).</em></u> (x - <em>h</em>)² + (y - <em>k</em>)² = <em>r</em>²
where <em>(h, k)</em> are coordinates of a center of the circle with radius <em>r</em>
<u><em>(2).</em></u> ( a ± b )² = a² ± 2ab + b²
~~~~~~~~~~~~~~
( 1 , - 2 ) ; r = 3
( x - 1 )² + ( y + 2 )² = 3²
x² - 2x + 1 + y² + 4y + 4 = 9
x² + y² - 2x + 4y - 4 = 0
a = - 2
b = 4
c = - 4
