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sammy [17]
3 years ago
13

If you switch to night shift, you will receive a 10% wage increase

Mathematics
2 answers:
Maksim231197 [3]3 years ago
3 0

What is your question?

hichkok12 [17]3 years ago
3 0
What is your question?
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On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y =
rosijanka [135]

Answer:

Well ,lets see∉ if you add theose numbers togetherФ it maybe it he answer is 4=67 *64  ---4 67x54 5xe4t4 6x

7 0
2 years ago
Work out the height of a parallelogram with base of 6cm and area of 27cm²
professor190 [17]
To find the height of the parallelogram you would divide 6 from the area, 27, to get the answer 4.5,
So h=4.5
5 0
3 years ago
Rewrite (123 + 456) + 789 using the Associative Law of Addition
adelina 88 [10]

Answer:

123 + (456 + 789)

Step-by-step explanation:

since this is an addition problem, the parenthesis don't matter, and they can be put wherever you want.

(123 + 456) + 789

123 + 456 + 789

(123 + 456 + 789)

123 + (456 + 789)

technically, any of these would work, but I think the kind of answer the problem is looking for is;

123 + (456 + 789)

5 0
3 years ago
(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
f(t)\equiv-5u(t)-u(t-1)+12u(t-7)
5 0
3 years ago
Instructions
Anuta_ua [19.1K]

Step-by-step explanation:

Drag the empty jar to the lake to get a water sample  

2. Fill two beakers with 600 ml water from the jar

3. Put the “1” and “2” labels on each beaker  

Take the pH meter to Beaker 1 and record the pH and description in Table A  

Take the pH meter to Beaker 2 and record the pH and description in Table B

 Add 1 unit of each base (soap, alkaline batteries, baking soda) to Beaker 2 and record the pH and description in Table B, and clear

This means that my hypothesis at the beginning was correct, more of m/s means KE will increase proportionally because they are all linear. I found it surprising when the bean bag height went over the water bottle drop mark.  

4.     To conclude, my hypothesis matched my data. The data values went up when more mass or speed was added. This means if I were in a situation where I needed more kinetic energy for something, I would know to increase mass or the speed of the object giving it energy.  

The reason that this hypothesis is correct is when you have more mass, you have more energy. So, when you drop let's say a baseball, it isn’t that heavy so it would only launch the bean bag so far. But a bowling ball is very heavy and has lots of energy when falling because of that, it would make the bean bag go very high.  

To make this experiment better, I would use a smoother material for the lever so energy wouldn’t be lost by friction from wood rubbing together. Also, maybe a scanner or video camera to more accurately record how far the bean bag went. All of these would help the lab get more precise results, maybe they could be used in a future lab.

7 0
2 years ago
Read 2 more answers
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