Answer:
a. Systems testing
Explanation:
According to my research on information technology, I can say that based on the information provided within the question the term being defined is called System Testing. Like mentioned in the question, this is a technique used in order to evaluate the complete system the system's compliance against specified requirements, which tests its functionalities from an end-to-end perspective in order to evaluates patches used to close software vulnerabilities and make sure it complies with all policies.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer: 4. Alma has a 3.81 GPA and misses 3 days of school
Explanation: The others don't meet the requirments.
Answer:
The ArrayList initial functionality is 5, there were 4 components.
Then, add 25 more elements by using add()calling 25 times So total number of elements after the completed operation would be 4 + 25= 29.
5th component will be introduced without calling ensureCapacity(); while adding 6th element-> ensureCapacity(2* 5+ 1) it will call, making the capacity 11.
So ArrayList's capacity will be 11.
Next 7th to 11th components will also be added automatically once the 12th element is added, it will name ensureCapacity(2* 11+ 1) and make the capacity 23.
While adding 24th dimension, ensureCapacity(2* 23+ 1) will be called again and this will make the capacity 47.
There will therefore be 3 (three) calls to ensure the feature Ability).
Elements of Rest 25th to 29th will be added seamlessly as ability becomes 47.
Given an array of integers (both odd and even), sort them in such a way that the first part of the array contains odd numbers sorted in descending order, rest portion contains even numbers sorted in ascending order.
Explanation:
- Partition the input array such that all odd elements are moved to left and all even elements on right. This step takes O(n).
- Once the array is partitioned, sort left and right parts individually. This step takes O(n Log n).
#include <bits/stdc++.h>
using namespace std;
void twoWaySort(int arr[], int n)
{
int l = 0, r = n - 1;
int k = 0;
while (l < r) {
while (arr[l] % 2 != 0) {
l++;
k++;
}
while (arr[r] % 2 == 0 && l < r)
r--;
if (l < r)
swap(arr[l], arr[r]);
}
sort(arr, arr + k, greater<int>());
sort(arr + k, arr + n);
}
int main()
{
int arr[] = { 1, 3, 2, 7, 5, 4 };
int n = sizeof(arr) / sizeof(int);
twoWaySort(arr, n);
for (int i = 0; i < n; i++)
cout << arr[i] << " ";
return 0;
}
Answer:
Only the last number of each IP address will be unique
Explanation:
Subnet Mask is used to identify the two parts of the IP address. One is the network part that should be same for one network, and other is host part that will vary with number of computer or devices that are connected to the network.
Subnet mask is 32 bit address that are divided in 4 equal parts of 8 bits. Each 8 bit converted to decimal by varying different bits to generate 256 different decimal number combinations. It means we can vary the address range between 0 to 255. So If any 8 bit portion is 255 that means, in this section we cannot add host address.
<u>For Example</u>
In given case,
Subnet Mask = 255.255.255.0
That means first three portions are fixed and has been allocated for network part.
The forth portion is 0 that means we can change this portion in IP address up to 255 different addresses.
So the IP address that is given can be vary as:
10.1.10. 186
10.1.10 This portion is network portion, this cannot be vary.
only the number 186 is the unique address that is particularly assigned to the devices and is vary between 0 to 255.
