What is the domain of the relation shown?

Jesse graph a point to represent the absolute value of a number line. If the original number is less than -10, describe all the

Anuta_ua [19.1K]

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4 0

2 years ago

Which term best describes a figure formed by three segments connecting

elixir [45]

Answer:

The term that best describes a figure formed by three segments connecting three non-collinear points is:

Triangle.

Step-by-step explanation:

Step-by-step explanation:

We know that with the help of just one point we can't form any figure.

With the help of two points a line segment can be formed.

And with the help of three points if the three points are collinear a triangle can be formed.

Hence, the term that best describes a figure formed by three segments connecting three non-collinear points is:

Triangle.

8 0

2 years ago

Compound interest

aev [14]

9514 1404 393

Answer:

4254.31

Step-by-step explanation:

The compound interest multiplier is ...

m = (1 +r/n)^(nt) . . . . annual rate r compounded n times per year, t years

For 11% compounded quarterly for 18 years, the multiplier is ...

m = (1 +0.11/4)^(4·18) = 1.0275^72 ≈ 7.0516671

If 30,000 is the future value, then the present value is ...

PV = FV/m = 30,000/7.0516671

PV ≈ 4254.31

3 0

1 year ago

The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$