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2 years ago

What’s the slope and y-intercept of y=x?

Mathematics

2 answers:

Gemiola [76]2 years ago

6 0

Answer:

y ints

Step-by-step explanation:

kotegsom [21]2 years ago

5 0

Answer:

Slope is 1; y-int is (0, 0)

Step-by-step explanation:

Step 1: Identify the slope

The slope is the number attached to the x. Since in this problem there is no number or sign, that means that number in front of it is 1.

y = 1x is same as y = x

So... the slope is 1

Step 2: Identify the y-int

The y-int is the number after the mx, also known as b. In this problem there is no number after, that means that the y-int is 0.

y = mx + b

y = 1x + 0

So... the y-int is (0, 0)

Answer: Slope is 1; y-int is (0, 0)

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24 is 4 times as great as Pls help

Vaselesa [24]

Answer:

6=k

Step-by-step explanation:

5 0

2 years ago

I’ve saved £264. I will spend 3/12 of this. How much do I have left?

lara [203]

Hi there! The answer is £198.

If you spend 3 / 12 of a certain amount of money, you have 9 / 12 of the money left.

Simplify the fraction.
9 / 12 = 3 / 4.

To find the amount of money left, we multiply this factor by 264. We get the following
£264 × 3/4 = £264 × 0.75 = £198

Therefore the answer is £198

7 0

3 years ago

In 1998, Cathy's age is equal to the sum of the four digits in the year of her birthday, then how old was Cathy in 1998?

ycow [4]

Answer:

Cathy was born in 1980 and she was 18 years old in 1998

Step-by-step explanation:

Equations

This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.

Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

$x=1000a+100b+10c+d$

In 1998, Cathy's age was

$1998-(1000a+100b+10c+d)$

And it must be equal to the sum of the four digits

$1998-(1000a+100b+10c+d)=a+b+c+d$

Rearranging

$1998=1001a+101b+11c+2d$

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

$1998=1001+909+11c+2d$

Operating

$88=11c+2d$

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]

c=8, d=0

Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18

5 0

3 years ago

Please help!

kogti [31]

I and III seem to be correct, II doesn't because, for example, if x = w = z = t = 70 and y = u = 40, then all three pairs of vertical angles in the figure have equal measure and the given condition x + y = u + w stands. But it means y is not equal to w.

3 0

3 years ago

Read 2 more answers

Solve the equation 3/y = 4/5

netineya [11]

Step-by-step explanation:

Step 1: Cross Multiply

$\frac{3}{y} = \frac{4}{5}$