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3 years ago

PLZ just do it :( 20 points???

Mathematics

2 answers:

Sedaia [141]3 years ago

5 0

The answer would be A, it has no solution

givi [52]3 years ago

3 0

A has no solution x cancelled out which means it had no solution

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Use the distributive property to multiply.<br><br> -(-16m-1)

Pepsi [2]

Answer:

16m+1

Step-by-step explanation:

Knowing about our proprieties about parentheses and negatives, let's solve this out.

<u>A negative multiplied by a negative give you a positive</u>

therefore....

-(-16m-1)= 16m+1

The -1 also receives the negative because the problem was in a parentheses :)

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3 years ago

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Gnoma [55]

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Nady [450]

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A fire burned a square - shaped forest 14mi on a side the area is ?

Tpy6a [65]

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3 years ago

Read 2 more answers

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago