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Why are handcuffs like souvenirs?

ArbitrLikvidat [17]

Part A) $7(a+b)=7a+$

Using the distributive property

$7(a+b)=7a+7b$

therefore

the answer Part A is

$9-----> A$

Part R) $4(5+x)=20+$

Using the distributive property

$4(5+x)=20+4x$

therefore

the answer Part R is

$14-----> R$

Part Y) $3(2x+9)=6x+$

Using the distributive property

$3(2x+9)=6x+27$

therefore

the answer Part Y is

$4-----> Y$

Part S) $8(3x+1)=+8$

Using the distributive property

$8(3x+1)=24x+8$

therefore

the answer Part S is

$23-----> S$

Part O) $a(4+b)=+ab$

Using the distributive property

$a(4+b)=4a+ab$

therefore

the answer Part O is

$17-----> O$

Part E) $x(y+10)=+10x$

Using the distributive property

$x(y+10)=xy+10x$

therefore

the answer Part E is

$3-----> E$

Part I) $2(7x+4y)=14x+$

Using the distributive property

$2(7x+4y)=14x+8y$

therefore

the answer Part I is

$20-----> I$

Part D) $6(9+5x)=54+$

Using the distributive property

$6(9+5x)=54+30x$

therefore

the answer Part D is

$10-----> D$

Part W) $x(a+3b)=+3bx$

Using the distributive property

$x(a+3b)=ax+3bx$

therefore

the answer Part W is

$18-----> W$

Part E) $a(8x+2y)=8ax+$

Using the distributive property

$a(8x+2y)=8ax+2ay$

therefore

the answer Part E is

$7-----> E$

Part T) $0.5(4a+10)=2a+$

Using the distributive property

Part T) $0.5(4a+10)=2a+5$

therefore

the answer Part T is

$1-----> T$

Part R) $(2/3)(12+9y)=8+$

Using the distributive property

$(2/3)(12+9y)=8+6y$

therefore

the answer Part R is

$6-----> R$

Part O) $5x+5y=5(x+\ )$

$5x+5y=5(x+y)$

therefore

the answer Part O is

$13-----> O$

Part T) $9a+9b=9(\ +b)$

$9a+9b=9(a+b)$

therefore

the answer Part T is

$22-----> T$

Part W) $4m+4n=\ (m+n)$

$4m+4n=4(m+n)$

therefore

the answer Part W is

$16-----> W$

Part H) $ab+3a=a(b+\ )$

$ab+3a=a(b+3)$

therefore

the answer Part H is

$2-----> H$

Part E) $xy+15x=\ (y+15)$

$xy+15x=x(y+15)$

therefore

the answer Part E is

$11-----> E$

Part A) $bu+uv=\ (b+v)$

$bu+uv=u(b+v)$

therefore

the answer Part A is

$5-----> A$

Part F) $(2/5)m+(2/5)n=(2/5)( \ +n)$

$(2/5)m+(2/5)n=(2/5)(m+n)$

therefore

the answer Part F is

$12-----> F$

Part M) $(3/4)a+(3/4)b+(3/4)c=\ (a+b+c)$

$(3/4)a+(3/4)b+(3/4)c=(3/4)(a+b+c)$

therefore

the answer Part M is

$8-----> M$

Part S) $7ax+2ay=a(7x+\ )$

$7ax+2ay=a(7x+2y)$

therefore

the answer Part S is

$21-----> S$

Part T) $4kx+11ky=\ (4x+11y)$

$4kx+11ky=k(4x+11y)$

therefore

the answer Part T is

$15-----> T$

Part R) $3ay+8by=y(\ +8b)$

$3ay+8by=y(3a+8b)$

therefore

the answer Part R is

$19-----> R$

the answer is

they are made for two wrists

4 0

3 years ago

Read 2 more answers

What is From 45.5 to 42?

Anon25 [30]

The answer is 19.11 hope this helps

4 0

2 years ago

Solve by unfolding: a0=2, and, n>=1, a_n=7a_n-1.

vodomira [7]

We are told that the first term is 2. The next term is 7(2) = 14; the third term is 7(14) = 98. And so on. So, the first term and the common ratio (7) are known.

The nth term of this geometric series is a_n = 2(7)^(n-1).

Check: What is the first term? We expect it is 2. 2(7)^(1-1) = 2(1) = 2. Correct.

What is the third term? We expect it is 98. 2(7)^(3-1) = 2(7)^2 = 98. Right.

6 0

2 years ago

A consumer affairs investigator records the repair cost for 4 randomly selected washers. A sample mean of $64.26 and standard de

Mashutka [201]

Answer:

Critical value: z = 1.28

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.80}{2} = 0.10$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$

So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

So

$M = 1.28*\frac{27.77}{\sqrt{4}} = 17.773$

The lower end of the interval is the mean subtracted by M. So 64.26 - 17.773 = $46.487.

The upper end of the interval is M added to the mean. So 64.26 + 17.773 = $82.033.

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

7 0

2 years ago

469.4 \62 estimate the quotient

bulgar [2K]

469.4/62=7.57

that is the answer

7 0

3 years ago