Answer:
Option (A)
Step-by-step explanation:
The vertices of square PQRS are P(−4, 7), Q(5, 4), R(2,−5) and S(−7,−2).
Now, Join the diagonals PR and QS,
now, PR=
=
=
Also, QS=
=
=
Therefore, PR is congruent to QS that is PR≅QS.
Slope of PR=
=
Slope of QS=
Thus, PR⊥QS.
Now, Mid point of PR=
=
=
Also, mid point of QS=
=
Therefore, (-1,1) is the mid point of both PR and QS, so PR and QS bisect each other.
Hence, option (A) is correct.