Here go to this website is has your answer
https://www.wyzant.com/resources/answers/173997/the_length_of_the_rectangle_is_7ft_more_than_twice_the_width_and_the_area_of_the_rectangle_is_99ft_squared_find_length_and_width
Answer:
28 degrees
Step-by-step explanation:
The given figure is an octagon. The sum of interior angles in an octagon is 1080. Thus, one can form an equation, add up all of the angle measures, and set the equation equal to 1080. Then simplify and use inverse operations to find the value of the parameter (t).
(150) + (3t + 34) + (5t) + (5t) + (3t + 37) + (7t - 49) + (5t - 16) + (5t) = 1080
Simplify,
33t + 156 = 1080
Inverse operations,
33t + 156 = 1080
-156 -156
33t = 924
/33 /33
t = 28
Answer:
A(max) = (9/2)*L² ft²
Dimensions:
x = 3*L feet
y = (3/2)*L ft
Step-by-step explanation:
Let call "x" and " y " sides of the rectangle. The side x is parallel to the wall of the house then
Area of the rectangle is
A(r) = x*y
And total length of fence available is 6*L f , and we will use the wall as one x side then, perimeter of the rectangle which is 2x + 2y becomes x + 2*y
Then
6*L = x + 2* y ⇒ y = ( 6*L - x ) /2
And the area as function of x is
A(x) = x* ( 6*L - x )/2
A(x) = ( 6*L*x - x² ) /2
Taking derivatives on both sides of the equation we get:
A´(x) = 1/2 ( 6*L - 2*x )
A´(x) = 0 ⇒ 1/2( 6*L - 2*x ) = 0
6*L - 2*x = 0
-2*x = - 6*L
x = 3*L feet
And
y = ( 6*L - x ) /2 ⇒ y = ( 6*L - 3*L )/ 2
y = ( 3/2)*L feet
And area maximum is:
A(max) = 3*L * 3/2*L
A(max) = (9/2)*L² f²
Answer:
Alright so let's start by elimination.
Step-by-step explanation:
It cannot be 1/4 (unless it's y or x)
Cannot be 1/2 unless it's the bottom part.
So that leaves you with 1/3 and 1/6, 1/6 is to small so it has to be 1/3.
Hope this helps!