A) part of it is decreasing, part of it is increasing.
Going left-to-right, the downhill/negative slope is the decreasing portion (x<-1) and the uphill/positive slope is the increasing portion (x>-1).
B) The x-intercepts are the points where the graph intersects the x-axis: (2,0) and (-4,0).
C: The y-intercept is the point where the graph intersects the y-axis: (0,-2).
D: There is no absolute maximum. The graph keeps going up forever.
E: The absolute minimum <u>point</u> is at that bottom, at (-1, -3). The absolute minimum <u>value</u> is -3, since that's the lowest y-value used.
Lets write this out:-
2.4 + 0.8 =______ - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
So to solve d blanks we will do d following:-
2.4 + 0.8 = 3.2
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.2 - 0.06 = 3.14
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.14 + 1.21= 4.25
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78=_____- 5.14=___
Now lets solve again:-
4.25 +1.78= 6.03
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14=___
Now lets solve again:-
6.03 - 5.14 = 0.89
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
So, 2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
Hope I helped ya!! xD
Answer:
384/12 or 192/6 or 96/3
Step-by-step explanation:
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
