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soldier1979 [14.2K]
3 years ago
11

Expand and simplify: 3x[(3 – x)(3+ x)]

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

Answer:

3x (9+3x-3x-x^2)

3x( 9-x^2)

= 27x-3x^3

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A water park sold 20 child tickets and 60 adult tickets. What is the percentage of the tickets sold were child?
natulia [17]

Answer:

Step-by-step explanation:

total tickets=20+60=80

percentage of child tickets sold=(20)/(80) ×100=25 %

3 0
3 years ago
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What's 5/4 + 1/4 in a mixed number answer. My calculator isn't functioning well. Thx!
lukranit [14]
It would be 1 1/2.

4/4 = 1
2/4 = 1/2

Hope this helped!
6 0
4 years ago
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What division problem does the model show? (Giving Brainliest To Whoever Answers Good)
Jobisdone [24]

Answer:

18÷18÷18

=0.05555555555

4 0
3 years ago
Service calls arriving at an electric company follow a Poisson distribution with an average arrival rate of 5656 per hour. Find
liberstina [14]

Answer:

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The variance is the same as the mean.

Average rate of 56 calls per hour:

This means that \mu = 56n, in which n is the number of hours.

Find the average and standard deviation of the number of service calls in a 15-minute period.

15 minute is one fourth of a hour, which means that n = \frac{1}{4}. So

\mu = 56n = \frac{56}{4} = 14

The variance is also 14, which means that the standard deviation is \sqrt{14} = 3.74

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

4 0
3 years ago
The length of the longer leg of a right triangle is 4 inches more than twice the length of the shorter leg. the length of the hy
Serjik [45]

The Pythagorean's Theorem for our situation would look like this:

shortleg^2+longleg^2=hypotenuse^2

So let's call the short leg s, the long leg l and the hypotenuse h. It appears that all our measurements are based on the measurement of the short leg. The long leg is 4 more than twice the short leg, so that expression is l=2s+4; the hypotenuse measure is 6 more than twice the short leg, so that expression is h=2s+6. And the short leg is just s. Now we can rewrite our formula accordingly:

s^2+(2s+4)^2=(2s+6)^2

And of course we have to expand. Doing that will leave us with

s^2+4s^2+8s+8s+16=4s^2+12s+12s+36

Combining like terms we have

5s^2+16s+16=4s^2+24s+36

Our job now is to get everything on one side of the equals sign and solve for s

s^2-8s-20=0

That is now a second degree polynomial, a quadratic to be exact, and it can be factored several different ways. The easiest is to figure what 2 numbers add to be -8 and multiply to be -20. Those numbers would be 10 and -2. Since we are figuring out the length of the sides, AND we know that the two things in math that will never EVER be negative are time and distance/length, -2 is not an option. That means that the short side, s, measures 10. The longer side, 2s+4, measures 2(10)+4 which is 24, and the hypotenuse, 2s+6, measures 2(10)+6 which is 26. So there you go!

6 0
4 years ago
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