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Sunny_sXe [5.5K]
2 years ago
15

Drag and Drop the correct answer into the boxes below.

Mathematics
1 answer:
scoray [572]2 years ago
7 0

Answer:

the first blank is 100

the second is 80

Step-by-step explanation:

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Points representing the length if a rectangle are located at A(0,0) and B(8,0). The width of the rectangle is one half its lengt
Anna35 [415]
The length is 8. Therefore, the width is 4.
The area of a rectangle is: 8*4=32 square units. The correct answer is (C)
8 0
3 years ago
Factor this problem ?<br> 125 +27y^3
koban [17]

Answer:

(5 + 3y)(25 - 15y + 9y²)

Step-by-step explanation:

This is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²), thus

125 + 27y³

= 5³ + (3y)³ with a = 5 and b = 3y

= (5 + 3y)(5² - 5(3y) + (3y)² )

= (5 + 3y)(25 - 15y + 9y²)

6 0
3 years ago
Help pls!!!
SVEN [57.7K]

Answer:

an = -6n + 5.

Step-by-step explanation:

This is an arithmetic sequence with first term a1 = -1 and common difference d = -6

an = a1 + d(n-1)

an = -1 + -6(n - 1)

an = -1 -6n + 6

an = -6n + 5.

3 0
3 years ago
What do all members of the family of linear functions f(x)=1m(x+3) have in common?
dsp73
All linear functions have in common...
1. Their highest exponent is 1.
2. The graphs of the equations are lines.

When finding things in common between different types of functions, you always have to look at the two sides of math; geometry and algebra. Geometry is all the graphs, and algebra is the equations.

I hope this helps!
7 0
3 years ago
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6
USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

The coordinates are given as:

\mathbf{(x,y) = (-60,0)\ (60,0)}

The center of the hyperbola  is  

\mathbf{(h,k) = (0,0)}

The distance from the center to the focal points is given as:

\mathbf{c = 60}

Square both sides

\mathbf{c^2 = 3600}

The distance from the receiver to the transmitters  is given as:

\mathbf{2a = 100}

Divide both sides by 2

\mathbf{a = 50}

Square both sides

\mathbf{a^2 = 2500}

We have:

\mathbf{b^2 = c^2 - a^2}

This gives

\mathbf{b^2 = 3600 - 2500}

\mathbf{b^2 = 1100}  

The equation of an hyperbola is:

\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}

So, we have:

\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}

\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Hence, the equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Read more about hyperbolas at:

brainly.com/question/15697124

7 0
3 years ago
Read 2 more answers
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