Ask question

Ask question

All categories

3 years ago

15

A rectangle has an area of 72 square units. The width of the rectangle is 9 units. The length of the rectangle is 2 x + 4. What

is the rectangle's length? 6 7 8 9

2 answers:

dimaraw [331]3 years ago

8 0

8

A=LW
72= 9(2x+4)
72= 18X+36
Sub 36
36= 18X
Divide by 18
X=2

Length (2(2)+4)=8

sukhopar [10]3 years ago

3 0

Answer:

the answer is 8

Step-by-step explanation:

You might be interested in

Joey can put together 4 budgets in 2 minutes. What is the unit rate for one burger?

Lisa [10]

30 seconds/per burger

7 0

3 years ago

Read 2 more answers

Amy and Mary are playing a board game that uses game money if $5 and $10. At the end of the game, Amy has n bills worth $5 each

loris [4]

Answer:

5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .

Step-by-step explanation:

As given

Amy and Mary are playing a board game that uses game money if $5 and $10.

At the end of the game, Amy has n bills worth $5 each and d bills worth $10 each .

Total amount of n bills = 5n

Total amount of d bills = 10d

Thus

Total money spend by the Amy in playing board games = Total amount of n bills + Total amount of d bills

= 5n + 10d

Therefore 5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .

6 0

3 years ago

Which statement is correct PLEASE HELP ILL GOVE YOU BRAINLIEST.

Valentin [98]

The first one is correct, just match the numbers with the corresponding sides of each triangle

6 0

3 years ago

PLZ I NEED THIS FAST

neonofarm [45]

Answer:

I believe the correct answer is A

Step-by-step explanation:

7 0

3 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

6 0

2 years ago