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densk [106]
3 years ago
8

A shipping container will be used to transport several 50-kilogram crates across the country by rail. The greatest weight that c

an be loaded into the container is 24000 kilograms. Other shipments weighing 3900 kilograms have already been loaded into the container. Write and solve an inequality which can be used to determine xx, the number of 50-kilogram crates that can be loaded into the shipping container.
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:

  • See below

Step-by-step explanation:

  • Capacity of the container = 24000 kg
  • Loaded weight = 3900 kg
  • Number of crates = x

<u>Required inequality:</u>

  • 50x + 3900 ≤ 24000

<u>Solving:</u>

  • 50x ≤ 20100
  • x ≤ 20100/50
  • x ≤ 402
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gladu [14]

Answer:

Part a) The graph in the attached figure (see the explanation)

Pat b)  see the explanation

Step-by-step explanation:

Part a)  Write and graph a system of linear inequalities that represents this situation

Let

x ----> the number of shirts you can buy

y ----> the number of pants you can buy

we know that

The word "at most" is the same that " less than or equal to"

The word "at least" is the same that " greater than or equal to"

so

x+y \leq 6 ----> inequality A

The amount you have to spend minus the number of shirts multiplied by its price minus the number of pants multiplied by its price must be greater than or equal to $20

110-12x-18y \geq 20

Rewrite

12x+18y\leq 90 ----> inequality B

using a graphing tool

see the attached figure

Part b) How many shirts and pairs of pants can you buy at the store?

The solution of the system of inequalities is the shaded area

The solution is all whole numbers included in the shaded area

Example

(0,5),(3,3),(6,0), (3,2),...

6 0
3 years ago
75% of all undergraduates are in the College, 10% are in Engineering, 8% are in Commerce, 4% are in Nursing, and 3% are in Archi
Hunter-Best [27]

Answer:

the probability a randomly selected student is a third-year that they are in the College is 0.1743

Step-by-step explanation:

Given information

75% College = C = 0.75

10% are in Engineering, Eng = 0.1

8% are in Commerce, Com = 0.08

4% are in Nursing, Nurs = 0.04

3% are in Architecture, Arch = 0.03

21% Third year student = S = 0.21

21% in the College = 0.21

25% in Engineering = 0.25

49% in Commerce = 0.49

57% in Nursing = 0.57

33% in Architecture = 0.33

P(SlC) = 0.75 x 0.21 = 0.1575 is the probability of third year student in college

P(SlEng) = 0.1 x 0.25 = 0.025

P(SlCom) = 0.08 x 0.49 = 0.0392

P(SlNurs) = 0.04 x 0.57 = 0.0288

P(SlArch) = 0.03 x 0.33 = 0.0099

P(S) = P(SlEng) + P(SlCom) + P(SlNurs) +P(SlArch)

       = 1- (0.025 + 0.0392 + 0.0288 + 0.0099)

       = 0.9031

The probability of third year student in college is

P(ClS) = P(SlC) / P(S)

           = 0.1575 / 0.9031

           = 0.1743

3 0
4 years ago
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Answer:

A.

Step-by-step explanation:

4 0
3 years ago
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