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jek_recluse [69]
3 years ago
6

Please help me out with this.

Mathematics
1 answer:
xenn [34]3 years ago
5 0

Answer:

80 rooms

Step-by-step explanation:

since 45% of the rooms are booked, and 36 rooms are booked, then this means that 36 = 45% of x.

then, you we have 45% × x = 36

or \frac{45}{100}  × x = 36

Multiplying both sides by 100 and dividing both sides by 45,

we have x = 36 ×  \frac{100}{45}

= \frac{3600}{45}  

x = 80

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PLEASE HURRY THIS IS DUE IN 20MIN
OverLord2011 [107]

This is not my answer I found it from another brainly

From the beginning we know we are dealing with two different rates. Distance is equal to (Speed X Time). We have two different speeds though. We will call the min speed = x and the max speed = y. With those two ideas in place we can make two equations for both Tony and Rae.

Tony:

2x+3.5y=355

Rae:

2x+3y=320

Now you can solve the equations by subtracting Rae's equation from Tony's

.5y=35 solve for y and you get 70

Now plug that y value back into either equation and you can solve for x. I'll use Rae's distance:

2x+3(70)=320

x=55

6 0
3 years ago
Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 h
stira [4]

Answer:

The percent of the parts are expected to fail before the 2100 hours is 0.15.

Step-by-step explanation:

Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.

To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.

Solution:

We will use z score formula

z=\frac{x-\mu}{\sigma}

Mean value = \mu = 2500

Standard deviation = \sigma = 135

We are supposed to find  If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?

So we are supposed to find P(z<2100)

so, x = 2100

Substitute the values in the formula

z=\frac{2100-2500}{135}

z=−2.96

Now to find P(z<2100) we will use z table

At z = −2.96 the value is 0.0015

So, In percent = .0015 \times 100=0.15\%

Hence The percent of the parts are expected to fail before the 2100 hours is 0.15.

5 0
3 years ago
What is the product of<br> 9/20 - 1/4
wlad13 [49]

Answer:

\frac{1}{5}

Step-by-step explanation:

\frac{9}{20} - \frac{1}{4}

Make sure they have a common denominator. To do so, you must find a number the both have in come. Here, the number they have in common is 20.

What times 4 equals 20? 5. Whatever you do to the denominator you must do to the numerator.

\frac{5}{5} × \frac{1}{4} = \frac{5}{20}

Now you have \frac{9}{20} - \frac{5}{20} = \frac{4}{20}

Then you can simplify \frac{4}{20} to \frac{1}{5} by dividing it by \frac{4}{4}

8 0
3 years ago
​$ 3000 for 3 years at 6​% compounded semiannually
Vanyuwa [196]
Included a pic of the solution and work.

7 0
3 years ago
Find the Pythagorean Triple (a,b,c) using the terms (x²-y², 2xy, x² +y²) for x &gt;y&gt; 0
Lemur [1.5K]

Answer:

64,120,136  

I think

Step-by-step explanation:

8 0
3 years ago
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