Determine if the sequence below is arithmetic or geometric and determine the

1 answer:

5 0

The sequence is arithmetic since the common difference that is equal
d=11-15=7-11=-4
a(n) = a1 +(n-1)d
a1=15
=
a(n) = 15+(n-1)-4

You might be interested in

Explain how you know that √10 is between 3 and 4? what would your estimate of √10 be??

raketka [301]

Answer:

Step-by-step explanation:

Welllllll.....

If you take the square root of 9, it's 3

if you take the square root if 16, it's 4

I would guess it to be about 3.2

4 0

2 years ago

Read 2 more answers

Given that (-9,8) is on the graph of f(x), find the

rodikova [14]

Answer:

the corresponding point for function f(x) + 2 would be (12, -8)

7 0

2 years ago

The population of a city (in millions) at time t (in years) is P(t)=2.6 e 0.005t , where t=0 is the year 2000. When will the pop

lora16 [44]

Answer:

year 2139

Step-by-step explanation:

The population will double when the factor e^(.005t) is 2.

e^(.005t) = 2

.005t = ln(2)

t = ln(2)/0.005 = 138.6

The population will be double its size at t=0 when t=138.6. That is the population will be about 5.2 million in the year 2139.

7 0

3 years ago

Solve using demoivres theorem

pashok25 [27]

It's difficult to make out, but I think the task is to expand

$(\sqrt3-i)^4$

Write the number in polar form first:

$\sqrt3-i=2e^{-i\pi/6}$

By DeMoivre's theorem, you have

$(\sqrt3-i)^4=\left(2e^{-i\pi/6}\right)^4=2^4e^{-i4\pi/6}=16e^{-i2\pi/3}$

and converting back to Cartesian form, this number is equivalent to

$16\left(\cos\dfrac{2\pi}3-i\sin\dfrac{2\pi}3\right)=16\left(-\dfrac12+-\dfrac{\sqrt3}2\right)=-8(1+i\sqrt3)$

3 0

2 years ago

What's 1.6 rounded to the nearest tenth

dem82 [27]

Are there anymore numbers after the six? If there is not then it si already rounded to the nearest tenth.

7 0

3 years ago

Read 2 more answers