Answer:
2/3 I think, If not please tell me !
Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
You can find the slope and y-intercept, and make an equation in slope- intercept form and them just plug in the other x values in the equation.
Answer: 432 units²
Step-by-step explanation:
The figure is composed by two trapezoids.
The formula for calculate the area of a trapezoid is:
Where "B" is the larger base, "b" is the smaller base and "h" is the height.
Let be 
the area of the figure, 
the area of the trapezoid on the left and 
the area of the trapezoid of the right. Then the area of the figure will be:
Substituting values, you get:
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