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devlian [24]
2 years ago
9

1+1I need help and fast i've been trying to solve this one for 30 minutes now.

Mathematics
1 answer:
Liula [17]2 years ago
6 0

Answer:

2

Step-by-step explanation:

somebody has to answer eventually lol

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Graph "-3n+4<25" on a line plot
Studentka2010 [4]

Answer:The solution is in the attached file

Step-by-step explanation:

6 0
2 years ago
How many distinct triangles can be formed for which m∠X = 51°, x = 5, and y = 2? zero one two
Vitek1552 [10]
From the law of sines, we have:

\displaystyle{ \frac{\sin \angle X}{x}= \frac{\sin \angle Y}{y}, 

where x and y are the sides opposite to angles X and Y, respectively.


Substituting the known values, we have:



\displaystyle{ \frac{51^{\circ}}{5}= \frac{\sin \angle Y}{2}, thus

                           \displaystyle{ \sin \angle Y=\frac{\sin 51^{\circ}}{5}\cdot2\approx \frac{0.777}{5}\cdot2=0.31.


Using a calculator, we can find that arcsin(0.31)=18 degrees, approximately.

We know that sine of (180-18)=162 degrees is also 0.31. But 162 and 51 degrees add up to more than 180 degrees.

Thus, there is only one triangle that can be formed under these conditions.


5 0
3 years ago
Read 2 more answers
What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10?
Sonja [21]

Since this equation is already in standard form, there is no need to convert it. Standard form is Ax + By = C. In this equation, 7 = A, 3 = B, and 10 = C. From standard form, Ax + By = C equals negative A over B.

7x + 3y = 10

↓

\displaystyle\ m= \frac{-7}{-3}

Then you'd simplify.

\displaystyle\ m=\frac{7}{3}

The slope cannot be simplified any more, so this would be the final answer.

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<em>- Marlon Nunez</em>

7 0
2 years ago
You've just received an order of silk flower arrangements from your wholesaler. You paid $20.00 each for them. Your store uses a
valkas [14]
The answer to your question is D
8 0
2 years ago
Read 2 more answers
Help urgent plz!❤️❤️❤️Please please urgently
sleet_krkn [62]

Answer:

Problem 2): \left \{x\, |\,0\leq x\leq 240\,\,\right \}

which agrees with answer C listed.

Problem 3) :  D = (-3, 6]  and R = [-5, 7]

which agrees with answer D listed

Step-by-step explanation:

Problem 2)

The Domain is the set of real numbers in which the function (given by a graph in this case) is defined. We see from the graph that the line is defined for all x values between 0 and 240. Such set, expressed in "set builder notation" is:

\left \{x\, |\,0\leq x\leq 240\,\right \}

Problem 3)

notice that the function contains information on the end points to specify which end-point should be included and which one should not. The one on the left (for x = -3 is an open dot, indicating that it should not be included in the function's definition, therefor the Domain starts at values of x strictly larger than -3. So we use the "parenthesis" delimiter in the interval notation for this end-point. On the other hand, the end point on the right is a solid dot, indicating that it should be included in the function's definition, then we use the "square bracket notation for that end-point when writing the Domain set in interval notation:

Domain = (-3, 6]

For the Range (the set of all those y-values connected to points in the Domain) we use the interval notation form:

Range = [-5, 7]

since there minimum y-value observed for the function is at -5 , and the maximum is at 7, with a continuum in between.

6 0
2 years ago
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