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3 years ago

The questions is on the picture

Mathematics

2 answers:

stiv31 [10]3 years ago

8 0

Answer:

-7>-12

2>-2

-5<-3

∣-9∣ = 9

∣13∣ = 13

∣-5∣ = 5

Step-by-step explanation:

Hope this helps.Please mark my answer as brainliest

allochka39001 [22]3 years ago

5 0

Answer:

EASY:

Step-by-step explanation:

-7 > -12

2 > -2

-5 < -3

|-9| is maybe 9.

|13| is 13.

|-5| is maybe 5.

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According to Lambert's law, the intensity of light from a single source on a flat surface at point P is given by Upper L equal

malfutka [58]

Answer:

(a) $L = k*(1 - sin^{2}(\theta))$

(b) L reaches its maximum value when θ = 0 because cos²(0) = 1

Step-by-step explanation:

Lambert's Law is given by:

$L = k*cos^{2}(\theta)$ (1)

(a) We can rewrite the above equation in terms of sine function using the following trigonometric identity:

$cos^{2}(\theta) + sin^{2}(\theta) = 1$

$cos^{2}(\theta) = 1 - sin^{2}(\theta)$ (2)

By entering equation (2) into equation (1) we have the equation in terms of the sine function:

$L = k*(1 - sin^{2}(\theta))$

(b) When θ = 0, we have:

$L = k*cos^{2}(\theta) = k*cos^{2}(0) = k$

We know that cos(θ) is a trigonometric function, between 1 and -1 and reaches its maximun values at nπ, when n = 0,1,2,3...

Hence, L reaches its maximum value when θ = 0 because cos²(0) = 1.

I hope it helps you!

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3 years ago

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Fofino [41]

The answer is C and D

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3 years ago

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2) Simplify 675 divided (6+9 divided by 3)=

Volgvan

6+9=15

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Divide the fractions. 9/2 divided by 4/10

mario62 [17]

Answer:

11 1/4

Step-by-step explanation:

9/2/4/10

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What is the value of "c" in the following quadratic? (Make sure the equation is in

garri49 [273]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}$

What is the value of c in the quadratic $\large\text{$x^2+28=-11x$}$ ?

$\rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding $\large\textit{11x}$ on both sides:-

$\large\text{$x^2+28-11x=0$}$

We can switch the order of 28 and -11x:-

$\large\text{$x^2-11x+28=0$}$

Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

$\large\text{$ax^2+bx+c=0$}$

Now we can just write our quadratic here:-

$\large\text{$x^2-11x+28=0$}$

Now, can you see what the value of "c" is?

An easy way to remember "c" in quadratics is:-

The "c" in quadratics is the constant.

Henceforth, we conclude that the value of "c" in the given quadratic is:-

$\Large\textbf{28}\Large\checkmark$

<h3> Good luck with your studies.</h3>

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

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