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rodikova [14]
2 years ago
15

A triangle has a perimeter of 48 feet. If the three sides of the triangle are n, 4n−2, and 4n−4, what is the length of each side

?
Mathematics
1 answer:
alexdok [17]2 years ago
3 0

Answer:

6; 22; 20 (ft.)

Step-by-step explanation:

1) if the length of the each side are: n; 4n-2 and 4n-4, then the expression of the perimeter can be written: P=n+4n-2+4n-4 or P=9n-6.

2) if according to the condition perimeter is 48 (ft.), then

9n-6=P; ⇔ 9n-6=48; n=6.

3) if n=6, then the required lengths of the sides are:

n=6 (ft.);

4n-2=22 (ft.);

4n-4=20 (ft.)

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