6. The graphs of y, = 0.2(25X-40) and y2 = 4(0.5x+1.75) are shown on the coordinate grid.
1 answer:
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The increase is an exponential increase in a multiplier
and as decimal 1.0045
Final Value = Initial Value ×
Final value =
Final value = 393 mg (to the nearest whole number)
Half life = 0.5 years
Final value =
=301 mg
Final Value = Initial Value ×
Final value =
Final value = 393 mg (to the nearest whole number)
Half life = 0.5 years
Final value =
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).
Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is = g/L
Outgoing rate =
Integrating both sides
[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram
Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get
Therefore the concentration of salt in the incoming brine is 1.73 g/L
<h2>Answer: -1.469</h2>
This trigonometric function can be written as:
(1)
Firstly, we have to solve the inner parenthesis:
(2)
Substituting (2) in (1):
(4)
Finally we obtain the value: