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masha68 [24]
3 years ago
13

(02.06 MC) Figure ABCD is a rhombus, and m∠BAE = 9x + 2 and m∠BAD = 130°. Solve for x. Rhombus ABCD with diagonals AC and BD and

point E as the point of intersection of the diagonals.
Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0

An angle bisector divides an angle into equal parts.

<em>The value of x is 7</em>

The given parameters are:

\angle BAE = 9x + 2

\angle BAD = 130^o

Line AE is the angle bisector of \angle BAD

This means that:

\angle BAD = 2 \times \angle BAE

So, we have:

130 = 2 \times (9x + 2)

Divide both sides by 2

65 = 9x + 2

Subtract 2 from both sides

63 = 9x

Divide both sides by 9

7 = x

Rewrite as:

x = 7

Hence, the value of x is 7

Read more about angle bisectors at:

brainly.com/question/12896755

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<u>Step-by-step explanation:</u>

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More can be learned about the mean of a discrete distribution at brainly.com/question/24245882

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