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GREYUIT [131]
3 years ago
6

What is the value of X in the equation 8X - 2y=48,when y=4

Mathematics
2 answers:
Anni [7]3 years ago
6 0

Answer:

x = 7.

Step-by-step explanation:

The given equation is  

8x-2y=48

We need to find the value of x, when y=4.

Substitute y=4 in the given equation and then solve for x.

8x-2(4)=48

8x-8=48

Add 8 on both sides.

8x=48+8

8x=56

Divide both sides by 8.

x=\dfrac{56}{8}

x=7

Therefore, the value of x is 7, when y=4.

Travka [436]3 years ago
3 0

Answer:

X=7

Step-by-step explanation:

8x-2y=48

8x-2(4)=48

8x-8=48

8(7)-8=48

56-8=48

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What are the solutions to x2 + x - 5≤0
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x≤3

---

hope it helps

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Is AB a tangent why or why not??​
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5 0
3 years ago
A triangle has two sides of length 12 and 6. What is the largest possible whole-number length
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3 years ago
Given a normal population whose mean is 675 and whose standard deviation is 44, find each of the following: A. The probability t
NNADVOKAT [17]

Answer:

27.88% probability that a random sample of 5 has a mean between 677 and 693.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 675, \sigma = 44, n = 5, s = \frac{44}{\sqrt{5}} = 19.6774

The probability that a random sample of 5 has a mean between 677 and 693.

This is the pvalue of Z when X = 693 subtracted by the pvalue of Z when X = 677. So

X = 693

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{693 - 675}{19.6774}

Z = 0.91

Z = 0.91 has a pvalue of 0.8186

X = 677

Z = \frac{X - \mu}{s}

Z = \frac{677 - 675}{19.6774}

Z = 0.1

Z = 0.1 has a pvalue of 0.5398

0.8186 - 0.5398 = 0.2788

27.88% probability that a random sample of 5 has a mean between 677 and 693.

5 0
4 years ago
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