Answer:
A=8.4063
Step-by-step explanation:
Be the functions:

according the graph:
=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%20%3D3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%3D3%28%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%29%3D3%5Blnx-%5Cfrac%7B1%7D%7Bx%7D%5D%281-7%29%3D3%5B%28ln7-ln1%29-%28%5Cfrac%7B1%7D%7B7%7D-1%29%5D%3D3%5B%281.945-0%29-%280.1428-1%29%5D%3D3%2A%281.945%2B0.8571%29%3D3%2A2.8021%3D8.4063u%5E%7B2%7D)
Here's one way to do it.
AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence
Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)
Multiply equation (1) by 2:
22x + 30y + 46 = 0
Multiply equation (2) by 15:
105x - 30y - 300 = 0
Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]
Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3
Therefore, x = 2 and y = -3.
Step-by-step explanation:
Since line NL is not necessarily congruent to MQ (labelled with different congruent marks), triangle NLM is not congruent to triangle MQP.
Instead, triangles NLM and QPM are congruent.